{"id":37253,"date":"2025-11-20T00:41:11","date_gmt":"2025-11-19T22:41:11","guid":{"rendered":"https:\/\/www.cpge-brizeux.fr\/wordpress\/non-classe\/conversion-de-puissance-3-conversion-electro-magneto-mecanique-2.html"},"modified":"2025-11-20T23:53:57","modified_gmt":"2025-11-20T21:53:57","slug":"conversion-de-puissance-3-conversion-electro-magneto-mecanique-2","status":"publish","type":"post","link":"https:\/\/www.cpge-brizeux.fr\/wordpress\/psi\/physchim-psi-2526\/conversion-de-puissance-3-conversion-electro-magneto-mecanique-2.html","title":{"rendered":"Conversion de puissance 3 : Conversion \u00e9lectro-magn\u00e9to-m\u00e9canique"},"content":{"rendered":"<h2>T\u00e9l\u00e9chargements<\/h2>\n<p><a href='https:\/\/www.cpge-brizeux.fr\/wordpress\/wp-content\/uploads\/conversion-de-puissance-3-conversion-electro-magneto-mecanique-poly.pdf'>Polycopi\u00e9<\/a><\/p>\n<p><a href='https:\/\/www.cpge-brizeux.fr\/wordpress\/wp-content\/uploads\/conversion-de-puissance-3-conversion-electro-magneto-mecanique-flashcards.apkg'>Flashcards Anki<\/a><\/p>\n<h2>Coups de pouce<\/h2>\n<p>Laisser la souris\/taper sur le texte pour l&rsquo;afficher.<\/p>\n<div class='coups-de-pouce'>\n<h5>Exercice 1<\/h5>\n<ol>\n<li>\n<ul>\n<li>\n    Quelles amplitudes complexes sont en fait r\u00e9elles si on prend <span style=\"display: inline-block\"><svg class=\"typst-frame\" style=\"overflow: visible; width: 0.345em; height: 0.683em;\" viewBox=\"0 0 3.795 7.513000000000001\" width=\"3.795pt\" height=\"7.513000000000001pt\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" xmlns:xlink=\"http:\/\/www.w3.org\/1999\/xlink\" xmlns:h5=\"http:\/\/www.w3.org\/1999\/xhtml\"><g><g class=\"typst-text\" transform=\"matrix(1 0 0 -1 0 7.513000000000001)\"><use xlink:href=\"#gB8F35D0CF3F7279F00B25A54932361F6\" x=\"0\" y=\"0\" fill=\"#000000\" fill-rule=\"nonzero\"\/><\/g><\/g><defs id=\"glyph\"><symbol id=\"gB8F35D0CF3F7279F00B25A54932361F6\" overflow=\"visible\"><path d=\"M 0 0m 3.124 6.831 c 0 0.29699993 -0.14300013 0.44000006 -0.44000006 0.44000006 c -0.3080001 0 -0.61599994 -0.3080001 -0.61599994 -0.6160002 c 0 -0.29699993 0.1539998 -0.43999958 0.45099998 -0.43999958 c 0.30799985 0 0.605 0.3079996 0.605 0.6159997 Z m -0.2750001 -5.3129997 c -0.2420001 -0.869 -0.5940001 -1.309 -1.045 -1.309 c -0.143 0 -0.22000003 0.09900001 -0.22000003 0.30800003 c 0 0.18699998 0.319 1.1329999 0.96800005 2.849 c 0.08799982 0.25300002 0.13199997 0.45099998 0.13199997 0.5940001 c 0 0.53900003 -0.37400007 0.93499994 -0.913 0.93499994 c -0.47300005 0 -0.847 -0.2750001 -1.122 -0.83599997 c -0.22 -0.45099998 -0.32999998 -0.74800014 -0.32999998 -0.89100003 c 0 -0.09899998 0.055000007 -0.14299989 0.176 -0.14299989 c 0.143 0 0.16499996 0.065999985 0.20899999 0.21999979 c 0.25300002 0.8800001 0.594 1.3200002 1.034 1.3200002 c 0.143 0 0.21999991 -0.09899998 0.21999991 -0.3080001 c 0 -0.1539998 -0.032999992 -0.32999992 -0.109999895 -0.53900003 c -0.25300002 -0.69299984 -0.5170001 -1.4299998 -0.7370001 -2.013 c -0.16499996 -0.44000006 -0.25299996 -0.73700005 -0.25299996 -0.89100003 c 0 -0.53900003 0.39599997 -0.935 0.92399997 -0.935 c 0.47299993 0 0.847 0.275 1.1220001 0.825 c 0.20899987 0.42900002 0.319 0.72599995 0.319 0.89100003 c 0 0.09899998 -0.055000067 0.15399992 -0.17600012 0.15399992 c -0.032999992 0 -0.19799995 -0.09899998 -0.19799995 -0.23099995 Z \"\/><\/symbol><\/defs><\/svg><\/span> commet origine des phases ?\n  <\/li>\n<li>\n    \u00c9crire la loi des mailles en utilisant les amplitudes complexes.\n  <\/li>\n<\/ul>\n<\/li>\n<li>\n<ul>\n<\/ul>\n<\/li>\n<li>\n<ul>\n<\/ul>\n<\/li>\n<\/ol>\n<h5>Exercice 2<\/h5>\n<ol>\n<li>\n<ul>\n<li>\n    Donner le champ magn\u00e9tique cr\u00e9\u00e9 par le sol\u00e9no\u00efde. D\u00e9terminer le flux de ce champ sur le cadre.\n  <\/li>\n<li>\n    Quelle est la direction du champ cr\u00e9\u00e9 par le sol\u00e9no\u00efde ? Quelle est celle de la surface \u00e9l\u00e9mentaire du cadre ?\n  <\/li>\n<li>\n    Quelle relation relie le flux mutuel et l\u2019inductance mutuelle ?\n  <\/li>\n<\/ul>\n<\/li>\n<li>\n<ul>\n<\/ul>\n<\/li>\n<li>\n<ul>\n<\/ul>\n<\/li>\n<li>\n<ul>\n<li>\n    Vers quelle position d\u2019\u00e9quilibre le couple \u00e9lectromagn\u00e9tique ram\u00e8ne-t-il le cadre ? Pour quelle position du cadre le flux est-il maximal ?\n  <\/li>\n<\/ul>\n<\/li>\n<\/ol>\n<h5>Exercice 3<\/h5>\n<ol>\n<li>\n<ul>\n<li>\n    \u00c0 quelle condition le couple moyen exerc\u00e9 par le moteur est-il non nul ?\n  <\/li>\n<\/ul>\n<\/li>\n<li>\n<ul>\n<li>\n    La r\u00e9sistance est n\u00e9glig\u00e9e.\n  <\/li>\n<\/ul>\n<\/li>\n<li>\n<ul>\n<\/ul>\n<\/li>\n<li>\n<ul>\n<li>\n    D\u2019apr\u00e8s la loi de Lenz-Faraday, quelle relation lie <span style=\"display: inline-block\"><svg class=\"typst-frame\" style=\"overflow: visible; width: 0.722em; height: 0.683em;\" viewBox=\"0 0 7.942 7.513000000000001\" width=\"7.942pt\" height=\"7.513000000000001pt\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" xmlns:xlink=\"http:\/\/www.w3.org\/1999\/xlink\" xmlns:h5=\"http:\/\/www.w3.org\/1999\/xhtml\"><g><g class=\"typst-text\" transform=\"matrix(1 0 0 -1 0 7.513000000000001)\"><use xlink:href=\"#gE078979248C5F39BB63049486DD6423D\" x=\"0\" y=\"0\" fill=\"#000000\" fill-rule=\"nonzero\"\/><\/g><path class=\"typst-shape\" fill=\"none\" stroke=\"#000000\" stroke-width=\"0.528\" stroke-linecap=\"butt\" stroke-linejoin=\"miter\" stroke-miterlimit=\"4\" transform=\"matrix(1 0 0 1 0 9.097000000000001)\" d=\"M 0 0h 7.942 \"\/><\/g><defs id=\"glyph\"><symbol id=\"gE078979248C5F39BB63049486DD6423D\" overflow=\"visible\"><path d=\"M 0 0m 4.422 1.474 c 0.71500015 0.055000067 1.342 0.27499998 1.9029999 0.638 c 0.6600003 0.44000006 0.99000025 0.99 0.99000025 1.6389999 c 0 0.64900017 -0.32999992 1.1989999 -0.99000025 1.6389999 c -0.5609999 0.37400007 -1.1879997 0.59400034 -1.9029999 0.64900017 v 0.572 c 0 0.14300013 0.011000156 0.23099995 0.04400015 0.28599977 c 0.05499983 0.12100029 0.36299992 0.18700027 0.9460001 0.18700027 h 0.4069996 v 0.4289999 c -0.29699993 -0.021999836 -0.9239998 -0.032999992 -1.8809998 -0.032999992 c -0.96799994 0 -1.595 0.011000156 -1.892 0.032999992 v -0.4289999 h 0.40700006 c 0.58299994 0 0.90199995 -0.055000305 0.957 -0.17600012 c 0.021999836 -0.05499983 0.032999992 -0.1539998 0.032999992 -0.29699993 v -0.572 c -0.704 -0.07700014 -1.3200002 -0.29699993 -1.8590001 -0.65999985 c -0.649 -0.42900038 -0.968 -0.9680004 -0.968 -1.6170001 c 0 -0.64900017 0.319 -1.1880002 0.95699996 -1.628 c 0.53900003 -0.36300004 1.1660001 -0.58300006 1.8700001 -0.6600001 v -0.57199997 c 0 -0.143 -0.011000156 -0.231 -0.032999992 -0.286 c -0.055000067 -0.12099999 -0.37400007 -0.187 -0.957 -0.187 h -0.40700006 v -0.429 c 0.29699993 0.022 0.924 0.033 1.881 0.033 c 0.96799994 0 1.5949998 -0.011 1.8919997 -0.033 v 0.429 h -0.4069996 c -0.5830002 0 -0.8910003 0.055000007 -0.9460001 0.17600003 c -0.032999992 0.054999948 -0.04400015 0.15399998 -0.04400015 0.297 Z m 0 4.235 c 1.144 -0.14300013 1.7160001 -0.7920003 1.7160001 -1.947 c 0 -1.1550002 -0.572 -1.8040001 -1.7160001 -1.9580001 Z m -0.97899985 -0.011000156 v -3.883 c -1.1000001 0.16500008 -1.6500001 0.8030001 -1.6500001 1.936 c 0 1.1329999 0.54999995 1.7820001 1.6500001 1.947 Z \"\/><\/symbol><\/defs><\/svg><\/span> \u00e0 <span style=\"display: inline-block\"><svg class=\"typst-frame\" style=\"overflow: visible; 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Attention aux unit\u00e9s.\n  <\/li>\n<\/ul>\n<\/li>\n<li>\n<ul>\n<li>\n    Que vaut le courant dans l\u2019essai n\u00b01 ? \u00c9crire la loi des mailles pour l\u2019essai n\u00b01 et en d\u00e9duire la force contre-\u00e9lectromotrice.\n  <\/li>\n<li>\n    \u00c9crire la loi des mailles pour l\u2019essai n\u00b02 en utilisant la valeur de <span style=\"display: inline-block\"><svg class=\"typst-frame\" style=\"overflow: visible; width: 0.722em; height: 0.683em;\" viewBox=\"0 0 7.942 7.513000000000001\" width=\"7.942pt\" height=\"7.513000000000001pt\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" xmlns:xlink=\"http:\/\/www.w3.org\/1999\/xlink\" xmlns:h5=\"http:\/\/www.w3.org\/1999\/xhtml\"><g><g class=\"typst-text\" transform=\"matrix(1 0 0 -1 0 7.513000000000001)\"><use xlink:href=\"#gE078979248C5F39BB63049486DD6423D\" x=\"0\" y=\"0\" fill=\"#000000\" fill-rule=\"nonzero\"\/><\/g><\/g><defs id=\"glyph\"><symbol id=\"gE078979248C5F39BB63049486DD6423D\" overflow=\"visible\"><path d=\"M 0 0m 4.422 1.474 c 0.71500015 0.055000067 1.342 0.27499998 1.9029999 0.638 c 0.6600003 0.44000006 0.99000025 0.99 0.99000025 1.6389999 c 0 0.64900017 -0.32999992 1.1989999 -0.99000025 1.6389999 c -0.5609999 0.37400007 -1.1879997 0.59400034 -1.9029999 0.64900017 v 0.572 c 0 0.14300013 0.011000156 0.23099995 0.04400015 0.28599977 c 0.05499983 0.12100029 0.36299992 0.18700027 0.9460001 0.18700027 h 0.4069996 v 0.4289999 c -0.29699993 -0.021999836 -0.9239998 -0.032999992 -1.8809998 -0.032999992 c -0.96799994 0 -1.595 0.011000156 -1.892 0.032999992 v -0.4289999 h 0.40700006 c 0.58299994 0 0.90199995 -0.055000305 0.957 -0.17600012 c 0.021999836 -0.05499983 0.032999992 -0.1539998 0.032999992 -0.29699993 v -0.572 c -0.704 -0.07700014 -1.3200002 -0.29699993 -1.8590001 -0.65999985 c -0.649 -0.42900038 -0.968 -0.9680004 -0.968 -1.6170001 c 0 -0.64900017 0.319 -1.1880002 0.95699996 -1.628 c 0.53900003 -0.36300004 1.1660001 -0.58300006 1.8700001 -0.6600001 v -0.57199997 c 0 -0.143 -0.011000156 -0.231 -0.032999992 -0.286 c -0.055000067 -0.12099999 -0.37400007 -0.187 -0.957 -0.187 h -0.40700006 v -0.429 c 0.29699993 0.022 0.924 0.033 1.881 0.033 c 0.96799994 0 1.5949998 -0.011 1.8919997 -0.033 v 0.429 h -0.4069996 c -0.5830002 0 -0.8910003 0.055000007 -0.9460001 0.17600003 c -0.032999992 0.054999948 -0.04400015 0.15399998 -0.04400015 0.297 Z m 0 4.235 c 1.144 -0.14300013 1.7160001 -0.7920003 1.7160001 -1.947 c 0 -1.1550002 -0.572 -1.8040001 -1.7160001 -1.9580001 Z m -0.97899985 -0.011000156 v -3.883 c -1.1000001 0.16500008 -1.6500001 0.8030001 -1.6500001 1.936 c 0 1.1329999 0.54999995 1.7820001 1.6500001 1.947 Z \"\/><\/symbol><\/defs><\/svg><\/span> donn\u00e9e.\n  <\/li>\n<li>\n    \u00c9crire le th\u00e9or\u00e8me de Pythagore dans le triangle apparaissant sur le diagramme de Fresnel.\n  <\/li>\n<\/ul>\n<\/li>\n<li>\n<ul>\n<li>\n    Utiliser la condition de synchronisme.\n  <\/li>\n<\/ul>\n<\/li>\n<li>\n<ul>\n<li>\n    \u00c9crire la loi des mailles dans un circuit statorique puis la repr\u00e9senter sur un diagramme de Fresnel. Repr\u00e9senter les angles <span style=\"display: inline-block\"><svg class=\"typst-frame\" style=\"overflow: visible; width: 0.654em; height: 0.683em;\" viewBox=\"0 0 7.194 7.513000000000001\" width=\"7.194pt\" height=\"7.513000000000001pt\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" xmlns:xlink=\"http:\/\/www.w3.org\/1999\/xlink\" xmlns:h5=\"http:\/\/www.w3.org\/1999\/xhtml\"><g><g class=\"typst-text\" transform=\"matrix(1 0 0 -1 0 7.513000000000001)\"><use xlink:href=\"#gEE756DF734A19957BD650DED8EE3111E\" x=\"0\" y=\"0\" fill=\"#000000\" fill-rule=\"nonzero\"\/><\/g><\/g><defs id=\"glyph\"><symbol id=\"gEE756DF734A19957BD650DED8EE3111E\" overflow=\"visible\"><path d=\"M 0 0m 5.533 4.862 c -0.1869998 0 -0.35200024 -0.032999992 -0.5170002 -0.08799982 c -0.69299984 -0.23100042 -1.1769998 -0.9130001 -1.4519999 -1.5400002 c -0.4619999 -1.023 -0.59399986 -1.441 -0.93499994 -2.596 c -1.1329999 0.231 -1.7049999 0.748 -1.7049999 1.562 c 0 0.737 0.51699996 1.8040001 0.88 2.222 c 0.065999985 0.07700014 0.09899998 0.13199997 0.09899998 0.16499996 c 0 0.09899998 -0.054999948 0.15400028 -0.176 0.15400028 c -0.18700004 0 -0.42900002 -0.31900024 -0.72599995 -0.95700026 c -0.29700005 -0.638 -0.45100003 -1.21 -0.45100003 -1.7049999 c 0 -1.144 0.869 -1.87 1.8700001 -2.112 l -0.5610001 -1.782 c -0.04400003 -0.12100005 -0.065999985 -0.19800007 -0.065999985 -0.23100007 c 0 -0.23099995 0.12100005 -0.352 0.36299992 -0.352 c 0.20900011 0 0.352 0.109999895 0.44000006 0.319 l 0.37400007 1.947 c 0.12100005 -0.011000007 0.22000003 -0.011000007 0.319 -0.011000007 c 0.90199995 0 1.7049999 0.352 2.4309998 1.056 c 0.7260003 0.704 1.0890002 1.5070001 1.0890002 2.409 c 0 0.8579998 -0.4510002 1.54 -1.276 1.54 Z m 0.8800001 -1.7820001 c 0 -0.69299984 -0.32999992 -1.298 -1.0009999 -1.8149999 c -0.62700033 -0.462 -1.2980003 -0.69299996 -2.0240002 -0.69299996 c -0.065999985 0 -0.13199997 0 -0.18700004 0.010999978 c -0.065999985 0 -0.09899998 0 -0.09899998 -0.010999978 c 0.16499996 0.86899996 0.26399994 1.3859999 0.3080001 1.54 c 0.25299978 0.86899996 1.0009997 2.0349998 2.0129998 2.0349998 c 0.6160002 0 0.99000025 -0.43999982 0.99000025 -1.0669999 Z \"\/><\/symbol><\/defs><\/svg><\/span> et <span style=\"display: inline-block\"><svg class=\"typst-frame\" style=\"overflow: visible; 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width: 0.7969999999999999em; height: 0.683em;\" viewBox=\"0 0 8.767 7.513000000000001\" width=\"8.767pt\" height=\"7.513000000000001pt\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" xmlns:xlink=\"http:\/\/www.w3.org\/1999\/xlink\" xmlns:h5=\"http:\/\/www.w3.org\/1999\/xhtml\"><g><g class=\"typst-text\" transform=\"matrix(1 0 0 -1 0 7.513000000000001)\"><use xlink:href=\"#g186FCAD76D71C277C65357E35DB42C97\" x=\"0\" y=\"0\" fill=\"#000000\" fill-rule=\"nonzero\"\/><\/g><path class=\"typst-shape\" fill=\"none\" stroke=\"#000000\" stroke-width=\"0.528\" stroke-linecap=\"butt\" stroke-linejoin=\"miter\" stroke-miterlimit=\"4\" transform=\"matrix(1 0 0 1 0 9.339)\" d=\"M 0 0h 6.413 \"\/><\/g><defs id=\"glyph\"><symbol id=\"g186FCAD76D71C277C65357E35DB42C97\" overflow=\"visible\"><path d=\"M 0 0m 7.381 7.48 c -0.20900011 0 -0.86899996 0.032999992 -1.0780001 0.032999992 c -0.16499996 0 -0.25299978 -0.08799982 -0.25299978 -0.25300026 c 0 -0.10999966 0.076999664 -0.16499996 0.21999979 -0.17599964 c 0.3080001 -0.011000156 0.4619999 -0.12100029 0.4619999 -0.3080001 c 0 -0.09899998 -0.05499983 -0.23099995 -0.1539998 -0.3959999 l -3.278 -5.203 l -0.7260001 5.632 c 0 0.1869998 0.23100019 0.2750001 0.704 0.2750001 c 0.22000003 0 0.319 0.076999664 0.319 0.26399994 c 0 0.11000013 -0.065999985 0.16499996 -0.19799995 0.16499996 c -0.24199986 0 -1.0999999 -0.032999992 -1.342 -0.032999992 c -0.21999991 0 -0.96799994 0.032999992 -1.188 0.032999992 c -0.16500002 0 -0.25300002 -0.08799982 -0.25300002 -0.25300026 c 0 -0.12099981 0.110000014 -0.17599964 0.319 -0.17599964 c 0.18699998 0 0.31899995 -0.022000313 0.407 -0.04400015 c 0.176 -0.05499983 0.16499996 -0.07700014 0.19799995 -0.28599977 l 0.85800004 -6.71 c 0.032999992 -0.187 0.12100005 -0.286 0.26399994 -0.286 c 0.14300013 0 0.25300002 0.07700001 0.34100008 0.22 l 3.9160001 6.226 c 0.25299978 0.3959999 0.4949999 0.64900017 0.737 0.74800014 c 0.16499996 0.076999664 0.3739996 0.12099981 0.6160002 0.13199997 c 0.120999336 0.01099968 0.17599964 0.08799982 0.18699932 0.25299978 c 0.011000633 0.12100029 -0.05499935 0.17600012 -0.18699932 0.17600012 c -0.16499996 0 -0.7260003 -0.032999992 -0.8910003 -0.032999992 Z \"\/><\/symbol><\/defs><\/svg><\/span> et <span style=\"display: inline-block\"><svg class=\"typst-frame\" style=\"overflow: visible; width: 0.792em; height: 0.683em;\" viewBox=\"0 0 8.712 7.513000000000001\" width=\"8.712pt\" height=\"7.513000000000001pt\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" xmlns:xlink=\"http:\/\/www.w3.org\/1999\/xlink\" xmlns:h5=\"http:\/\/www.w3.org\/1999\/xhtml\"><g><g class=\"typst-text\" transform=\"matrix(1 0 0 -1 0 7.513000000000001)\"><use xlink:href=\"#gCBBF8E2F005F15E2987AA809752A3D2B\" x=\"0\" y=\"0\" fill=\"#000000\" fill-rule=\"nonzero\"\/><\/g><path class=\"typst-shape\" fill=\"none\" stroke=\"#000000\" stroke-width=\"0.528\" stroke-linecap=\"butt\" stroke-linejoin=\"miter\" stroke-miterlimit=\"4\" transform=\"matrix(1 0 0 1 0 9.097)\" d=\"M 0 0h 8.118 \"\/><\/g><defs id=\"glyph\"><symbol id=\"gCBBF8E2F005F15E2987AA809752A3D2B\" overflow=\"visible\"><path d=\"M 0 0m 2.189 7.216 c 0 -0.11000013 0.12100005 -0.16499996 0.352 -0.16499996 c 0.44000006 0 0.6600001 -0.04400015 0.6600001 -0.14300013 c 0 -0.032999992 -0.022000074 -0.11000013 -0.055000067 -0.25300026 l -1.43 -5.753 c -0.054999948 -0.24200004 -0.16499996 -0.385 -0.32999992 -0.44 c -0.07700002 -0.022000015 -0.2750001 -0.033000022 -0.61600006 -0.033000022 c -0.24199998 0 -0.352 -0.021999985 -0.352 -0.253 c 0 -0.121 0.12099999 -0.176 0.352 -0.176 h 5.643 c 0.26399994 0 0.28599977 0.022 0.37400007 0.20899999 l 0.43999958 0.99 c 0.2970004 0.68200004 0.50600004 1.1880001 0.62700033 1.5289999 c -0.022000313 0.09899998 -0.055000305 0.16499996 -0.17600012 0.16499996 c -0.07700014 0 -0.14300013 -0.05499983 -0.1869998 -0.1539998 c -0.2750001 -0.64900017 -0.53900003 -1.144 -0.80300045 -1.496 c -0.43999958 -0.59400004 -1.0889997 -0.814 -2.1229997 -0.814 h -1.595 c -0.11000013 0 -0.18700004 0 -0.23099995 0.011000007 c -0.065999985 0 -0.099000216 0.022000015 -0.099000216 0.055000007 c 0 0.022000015 0.022000074 0.09899998 0.055000067 0.24199998 l 0.7260001 2.937 h 1.0450001 c 0.5169997 0 0.7919998 -0.065999985 0.8470001 -0.20900011 c 0.021999836 -0.05499983 0.032999992 -0.13199997 0.032999992 -0.24199986 c 0 -0.14300013 -0.022000313 -0.319 -0.07700014 -0.5280001 c -0.022000313 -0.055000067 -0.032999992 -0.09899998 -0.032999992 -0.13199997 c 0 -0.109999895 0.065999985 -0.16499996 0.1869998 -0.16499996 c 0.09899998 0 0.16499996 0.08800006 0.20900011 0.25300002 l 0.6160002 2.552 c 0 0.11000013 -0.055000305 0.16499996 -0.17600012 0.16499996 c -0.08799982 0 -0.15400028 -0.07700014 -0.18700027 -0.23099995 c -0.10999966 -0.4289999 -0.25299978 -0.704 -0.43999958 -0.83599997 c -0.18700027 -0.13199997 -0.49500036 -0.19799995 -0.9460001 -0.19799995 h -0.9680002 l 0.63800025 2.5629997 c 0.08799982 0.37400007 0.08799982 0.38500023 0.5499997 0.38500023 h 1.5290003 c 0.5609999 0 0.9459996 -0.055000305 1.1549997 -0.16499996 c 0.3080001 -0.16499996 0.4619999 -0.49500036 0.4619999 -0.99000025 c 0 -0.1869998 -0.01099968 -0.38499975 -0.043999672 -0.572 c 0 -0.021999836 0 -0.05499983 -0.011000156 -0.09899998 v -0.09899998 c 0 -0.12099981 0.05499983 -0.17600012 0.16499996 -0.17600012 c 0.11000013 0 0.17600012 0.09899998 0.19800043 0.3080001 l 0.21999931 1.881 c 0.032999992 0.3080001 -0.043999672 0.34100008 -0.3409996 0.34100008 h -5.4890003 c -0.25300002 0 -0.37400007 -0.011000156 -0.37400007 -0.26399994 Z \"\/><\/symbol><\/defs><\/svg><\/span> sur l\u2019axe des abscisses. En d\u00e9duire une relation math\u00e9matique en utilisant la trigonom\u00e9trie.\n  <\/li>\n<\/ul>\n<\/li>\n<li>\n<ul>\n<li>\n    Attention, il y a deux phases \u00e0 prendre en compte.\n  <\/li>\n<li>\n    Rappel des hypoth\u00e8ses : pertes Joules n\u00e9gligeables.\n  <\/li>\n<\/ul>\n<\/li>\n<li>\n<ul>\n<li>\n    Exprimer la puissance m\u00e9canique en fonction du couple et de la vitesse angulaire puis la relier avec l\u2019expression de la question pr\u00e9c\u00e9dente.\n  <\/li>\n<li>\n    Pour quelle valeur de <span style=\"display: inline-block\"><svg class=\"typst-frame\" style=\"overflow: visible; width: 0.778em; height: 0.683em;\" viewBox=\"0 0 8.558 7.513000000000001\" width=\"8.558pt\" height=\"7.513000000000001pt\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" xmlns:xlink=\"http:\/\/www.w3.org\/1999\/xlink\" xmlns:h5=\"http:\/\/www.w3.org\/1999\/xhtml\"><g><g class=\"typst-text\" transform=\"matrix(1 0 0 -1 0 7.513000000000001)\"><use xlink:href=\"#gAE2565296987841CA0FB16F1461A6F87\" x=\"0\" y=\"0\" fill=\"#000000\" fill-rule=\"nonzero\"\/><\/g><\/g><defs id=\"glyph\"><symbol id=\"gAE2565296987841CA0FB16F1461A6F87\" overflow=\"visible\"><path d=\"M 0 0m 3.751 1.474 v -0.57199997 c 0 -0.143 -0.010999918 -0.231 -0.04399991 -0.286 c -0.055000067 -0.12099999 -0.36300015 -0.187 -0.9460001 -0.187 h -0.40699983 v -0.429 c 0.29699993 0.022 0.9239998 0.033 1.881 0.033 c 0.96799994 0 1.5949998 -0.011 1.8919997 -0.033 v 0.429 h -0.40700006 c -0.5829997 0 -0.8909998 0.055000007 -0.9459996 0.17600003 c -0.032999992 0.054999948 -0.04400015 0.15399998 -0.04400015 0.297 v 0.57199997 c 1.6389999 0.20899999 2.453 1.254 2.453 3.1350002 c 0 0.14299965 0.021999836 0.35199976 0.076999664 0.62699986 c 0.055000305 0.32999992 0.22000027 0.5169997 0.4840002 0.5499997 c 0.12099981 0.011000156 0.17600012 0.065999985 0.17600012 0.16499996 c 0 0.099000454 -0.09899998 0.15400028 -0.3080001 0.15400028 h -0.40700006 c -0.21999979 0 -0.3959999 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0.29699993 -1.3310003 c 0 -1.6169999 0.93500006 -2.6619997 2.387 -2.8709998 Z \"\/><\/symbol><\/defs><\/svg><\/span> le couple est-il maximal ?\n  <\/li>\n<\/ul>\n<\/li>\n<li>\n<ul>\n<li>\n    Repr\u00e9senter le diagramme de Fresnel et utiliser la trigonom\u00e9trie pour d\u00e9terminer <span style=\"display: inline-block\"><svg class=\"typst-frame\" style=\"overflow: visible; width: 0.654em; height: 0.683em;\" viewBox=\"0 0 7.194 7.513000000000001\" width=\"7.194pt\" height=\"7.513000000000001pt\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" xmlns:xlink=\"http:\/\/www.w3.org\/1999\/xlink\" xmlns:h5=\"http:\/\/www.w3.org\/1999\/xhtml\"><g><g class=\"typst-text\" transform=\"matrix(1 0 0 -1 0 7.513000000000001)\"><use xlink:href=\"#gEE756DF734A19957BD650DED8EE3111E\" x=\"0\" y=\"0\" fill=\"#000000\" fill-rule=\"nonzero\"\/><\/g><\/g><defs id=\"glyph\"><symbol id=\"gEE756DF734A19957BD650DED8EE3111E\" overflow=\"visible\"><path d=\"M 0 0m 5.533 4.862 c -0.1869998 0 -0.35200024 -0.032999992 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-0.69299984 -0.32999992 -1.298 -1.0009999 -1.8149999 c -0.62700033 -0.462 -1.2980003 -0.69299996 -2.0240002 -0.69299996 c -0.065999985 0 -0.13199997 0 -0.18700004 0.010999978 c -0.065999985 0 -0.09899998 0 -0.09899998 -0.010999978 c 0.16499996 0.86899996 0.26399994 1.3859999 0.3080001 1.54 c 0.25299978 0.86899996 1.0009997 2.0349998 2.0129998 2.0349998 c 0.6160002 0 0.99000025 -0.43999982 0.99000025 -1.0669999 Z \"\/><\/symbol><\/defs><\/svg><\/span> puis <span style=\"display: inline-block\"><svg class=\"typst-frame\" style=\"overflow: visible; width: 0.7969999999999999em; height: 0.683em;\" viewBox=\"0 0 8.767 7.513000000000001\" width=\"8.767pt\" height=\"7.513000000000001pt\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" xmlns:xlink=\"http:\/\/www.w3.org\/1999\/xlink\" xmlns:h5=\"http:\/\/www.w3.org\/1999\/xhtml\"><g><g class=\"typst-text\" transform=\"matrix(1 0 0 -1 0 7.513000000000001)\"><use xlink:href=\"#g186FCAD76D71C277C65357E35DB42C97\" x=\"0\" y=\"0\" fill=\"#000000\" fill-rule=\"nonzero\"\/><\/g><\/g><defs id=\"glyph\"><symbol id=\"g186FCAD76D71C277C65357E35DB42C97\" overflow=\"visible\"><path d=\"M 0 0m 7.381 7.48 c -0.20900011 0 -0.86899996 0.032999992 -1.0780001 0.032999992 c -0.16499996 0 -0.25299978 -0.08799982 -0.25299978 -0.25300026 c 0 -0.10999966 0.076999664 -0.16499996 0.21999979 -0.17599964 c 0.3080001 -0.011000156 0.4619999 -0.12100029 0.4619999 -0.3080001 c 0 -0.09899998 -0.05499983 -0.23099995 -0.1539998 -0.3959999 l -3.278 -5.203 l -0.7260001 5.632 c 0 0.1869998 0.23100019 0.2750001 0.704 0.2750001 c 0.22000003 0 0.319 0.076999664 0.319 0.26399994 c 0 0.11000013 -0.065999985 0.16499996 -0.19799995 0.16499996 c -0.24199986 0 -1.0999999 -0.032999992 -1.342 -0.032999992 c -0.21999991 0 -0.96799994 0.032999992 -1.188 0.032999992 c -0.16500002 0 -0.25300002 -0.08799982 -0.25300002 -0.25300026 c 0 -0.12099981 0.110000014 -0.17599964 0.319 -0.17599964 c 0.18699998 0 0.31899995 -0.022000313 0.407 -0.04400015 c 0.176 -0.05499983 0.16499996 -0.07700014 0.19799995 -0.28599977 l 0.85800004 -6.71 c 0.032999992 -0.187 0.12100005 -0.286 0.26399994 -0.286 c 0.14300013 0 0.25300002 0.07700001 0.34100008 0.22 l 3.9160001 6.226 c 0.25299978 0.3959999 0.4949999 0.64900017 0.737 0.74800014 c 0.16499996 0.076999664 0.3739996 0.12099981 0.6160002 0.13199997 c 0.120999336 0.01099968 0.17599964 0.08799982 0.18699932 0.25299978 c 0.011000633 0.12100029 -0.05499935 0.17600012 -0.18699932 0.17600012 c -0.16499996 0 -0.7260003 -0.032999992 -0.8910003 -0.032999992 Z \"\/><\/symbol><\/defs><\/svg><\/span>.\n  <\/li>\n<\/ul>\n<\/li>\n<\/ol>\n<h5>Exercice 5<\/h5>\n<ol>\n<li>\n<ul>\n<li>\n    Exprimer la puissance apparente nominale en fonction de la tension nominale et du courant nominal.\n  <\/li>\n<\/ul>\n<\/li>\n<li>\n<ul>\n<li>\n    Utiliser le courant de court-circuit.\n  <\/li>\n<li>\n    Repr\u00e9senter le circuit \u00e9quivalent d\u2019une phase en court-circuit.\n  <\/li>\n<li>\n    Repr\u00e9senter le diagramme de Fresnel associ\u00e9 \u00e0 la loi des mailles pour un induit court-circuit\u00e9.\n  <\/li>\n<li>\n    Utiliser le th\u00e9or\u00e8me de Pythagore.\n  <\/li>\n<\/ul>\n<\/li>\n<li>\n<ul>\n<\/ul>\n<\/li>\n<li>\n<ul>\n<li>\n    Placer l\u2019angle <span style=\"display: inline-block\"><svg class=\"typst-frame\" style=\"overflow: visible; width: 0.654em; height: 0.683em;\" viewBox=\"0 0 7.194 7.513000000000001\" width=\"7.194pt\" height=\"7.513000000000001pt\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" xmlns:xlink=\"http:\/\/www.w3.org\/1999\/xlink\" xmlns:h5=\"http:\/\/www.w3.org\/1999\/xhtml\"><g><g class=\"typst-text\" transform=\"matrix(1 0 0 -1 0 7.513000000000001)\"><use xlink:href=\"#gEE756DF734A19957BD650DED8EE3111E\" x=\"0\" y=\"0\" fill=\"#000000\" fill-rule=\"nonzero\"\/><\/g><\/g><defs id=\"glyph\"><symbol id=\"gEE756DF734A19957BD650DED8EE3111E\" overflow=\"visible\"><path d=\"M 0 0m 5.533 4.862 c -0.1869998 0 -0.35200024 -0.032999992 -0.5170002 -0.08799982 c -0.69299984 -0.23100042 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c -0.62700033 -0.462 -1.2980003 -0.69299996 -2.0240002 -0.69299996 c -0.065999985 0 -0.13199997 0 -0.18700004 0.010999978 c -0.065999985 0 -0.09899998 0 -0.09899998 -0.010999978 c 0.16499996 0.86899996 0.26399994 1.3859999 0.3080001 1.54 c 0.25299978 0.86899996 1.0009997 2.0349998 2.0129998 2.0349998 c 0.6160002 0 0.99000025 -0.43999982 0.99000025 -1.0669999 Z \"\/><\/symbol><\/defs><\/svg><\/span> sur le diagramme.\n  <\/li>\n<li>\n    Projeter <span style=\"display: inline-block\"><svg class=\"typst-frame\" style=\"overflow: visible; width: 2.183em; height: 0.683em;\" viewBox=\"0 0 24.012999999999998 7.513000000000001\" width=\"24.012999999999998pt\" height=\"7.513000000000001pt\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" xmlns:xlink=\"http:\/\/www.w3.org\/1999\/xlink\" xmlns:h5=\"http:\/\/www.w3.org\/1999\/xhtml\"><g><g class=\"typst-text\" transform=\"matrix(1 0 0 -1 0 7.513000000000001)\"><use xlink:href=\"#g7E1B7610964C28DE51BCBF606EE90D00\" x=\"0\" y=\"0\" fill=\"#000000\" 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0.17600012 c -0.26399994 0 -1.1110001 -0.032999992 -1.375 -0.032999992 c -0.23099995 0 -0.99 0.032999992 -1.221 0.032999992 c -0.16499996 0 -0.2420001 -0.08799982 -0.2420001 -0.26399994 c 0 -0.11000013 0.099000216 -0.16499996 0.29700017 -0.16499996 c 0.4949999 0 0.6489999 0 0.7809999 -0.31900024 l 1.2760003 -3.0029998 l -2.288 -2.453 c -0.03300023 -0.032999992 -0.07700014 -0.07700002 -0.13200021 -0.110000014 c -0.45099986 -0.473 -0.96799994 -0.737 -1.573 -0.77 c -0.187 -0.011000007 -0.286 -0.109999985 -0.286 -0.27499998 c 0.032999992 -0.099 0.044 -0.154 0.187 -0.154 c 0.187 0 0.83599997 0.033 1.023 0.033 c 0.23100007 0 0.99 -0.033 1.221 -0.033 c 0.16499996 0 0.2420001 0.088 0.2420001 0.264 c 0 0.09900001 -0.055000067 0.15399998 -0.17600012 0.16499999 c -0.26399994 0.022000015 -0.3959999 0.12100002 -0.3959999 0.28599998 c 0 0.110000014 0.09899998 0.264 0.286 0.46200007 c 0.6819999 0.72599995 1.375 1.4519999 2.046 2.189 c 0.37400007 -0.89100003 0.7589998 -1.7709999 1.1219997 -2.6729999 c 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<\/li>\n<\/ul>\n<\/li>\n<li>\n<ul>\n<li>\n    Exprimer la puissance fournie au r\u00e9seau par l\u2019alternateur en fonction de <span style=\"display: inline-block\"><svg class=\"typst-frame\" style=\"overflow: visible; width: 0.7969999999999999em; height: 0.683em;\" viewBox=\"0 0 8.767 7.513000000000001\" width=\"8.767pt\" height=\"7.513000000000001pt\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" xmlns:xlink=\"http:\/\/www.w3.org\/1999\/xlink\" xmlns:h5=\"http:\/\/www.w3.org\/1999\/xhtml\"><g><g class=\"typst-text\" transform=\"matrix(1 0 0 -1 0 7.513000000000001)\"><use xlink:href=\"#g186FCAD76D71C277C65357E35DB42C97\" x=\"0\" y=\"0\" fill=\"#000000\" fill-rule=\"nonzero\"\/><\/g><\/g><defs id=\"glyph\"><symbol id=\"g186FCAD76D71C277C65357E35DB42C97\" overflow=\"visible\"><path d=\"M 0 0m 7.381 7.48 c -0.20900011 0 -0.86899996 0.032999992 -1.0780001 0.032999992 c -0.16499996 0 -0.25299978 -0.08799982 -0.25299978 -0.25300026 c 0 -0.10999966 0.076999664 -0.16499996 0.21999979 -0.17599964 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Attention, on \u00e9tudie un alternateur diphas\u00e9.\n  <\/li>\n<li>\n    Comment s\u2019exprimer les pertes joules statoriques ?\n  <\/li>\n<\/ul>\n<\/li>\n<\/ol>\n<h5>Exercice 6<\/h5>\n<ol>\n<li>\n<ul>\n<li>\n    \u00c9crire une \u00e9quation \u00e9lectrique et une \u00e9quation m\u00e9canique et utiliser les relations entre grandeurs m\u00e9caniques et \u00e9lectriques pour une machine \u00e0 courant continu.\n  <\/li>\n<li>\n    Pour l\u2019\u00e9quation \u00e9lectrique, \u00e9crire la loi des mailles dans le circuit \u00e9lectrique \u00e9quivalent de l\u2019induit.\n  <\/li>\n<li>\n    Pour l\u2019\u00e9quation m\u00e9canique, \u00e9crire le th\u00e9or\u00e8me du moment cin\u00e9tique au syst\u00e8me masse + cable + poulie + rotor.\n  <\/li>\n<\/ul>\n<\/li>\n<\/ol>\n<h5>Exercice 7<\/h5>\n<ol>\n<li>\n<ul>\n<li>\n    Le couple dont on demande l\u2019expression est le couple qui s\u2019exerce <strong>sur<\/strong> la machine.\n  <\/li>\n<\/ul>\n<\/li>\n<li>\n<ul>\n<li>\n    \u00c9crire une \u00e9quation \u00e9lectrique et une \u00e9quation m\u00e9canique et utiliser les relations entre grandeurs m\u00e9caniques et \u00e9lectriques pour une machine \u00e0 courant continu.\n  <\/li>\n<li>\n    Pour l\u2019\u00e9quation \u00e9lectrique, \u00e9crire la loi des mailles dans le circuit \u00e9lectrique \u00e9quivalent de l\u2019induit.\n  <\/li>\n<li>\n    Pour l\u2019\u00e9quation m\u00e9canique, \u00e9crire le th\u00e9or\u00e8me du moment cin\u00e9tique au rotor.\n  <\/li>\n<\/ul>\n<\/li>\n<li>\n<ul>\n<li>\n    Calculer la tension aux bornes du moteur. Est-elle \u00e9gale \u00e0 la tension nominale ?\n  <\/li>\n<\/ul>\n<\/li>\n<\/ol>\n<h5>Exercice 8<\/h5>\n<ol>\n<li>\n<ul>\n<\/ul>\n<\/li>\n<\/ol>\n<h5>Exercice 9<\/h5>\n<ol>\n<li>\n<ul>\n<li>\n    Dans quelle partie du moteur les \u00e9tincelles se forment-elles ?\n  <\/li>\n<li>\n    Qu\u2019est-ce qui peut provoquer la formation d\u2019\u00e9tincelles ?\n  <\/li>\n<\/ul>\n<\/li>\n<\/ol>\n<h5>Exercice 10<\/h5>\n<ol>\n<li>\n<ul>\n<li>\n    Dans les conditions nominales, quelle est la puissance m\u00e9canique fournie par le moteur ? Quelle est la puissance \u00e9lectrique consomm\u00e9e ?\n  <\/li>\n<li>\n    La puissance \u00e9lectrique est consomm\u00e9e par l\u2019induit et par l\u2019inducteur.\n  <\/li>\n<\/ul>\n<\/li>\n<\/ol>\n<h5>Exercice 11<\/h5>\n<ol>\n<li>\n<ul>\n<li>\n    Que vaut la constante de couplage du moteur ?\n  <\/li>\n<li>\n    Que vaut la r\u00e9sistance de l\u2019induit ?\n  <\/li>\n<li>\n    Quelles sont les pertes cuivre dans les conditions nominales ?\n  <\/li>\n<li>\n    Faire un bilan de puissance sur l\u2019induit.\n  <\/li>\n<\/ul>\n<\/li>\n<\/ol>\n<h5>Exercice 12<\/h5>\n<ol>\n<li>\n<ul>\n<li>\n    Does the motor looks like a synchronous or DC motor?\n  <\/li>\n<li>\n    What important part is missing for the motor to work?\n  <\/li>\n<\/ul>\n<\/li>\n<\/ol><\/div>\n","protected":false},"excerpt":{"rendered":"<p>T\u00e9l\u00e9chargements Polycopi\u00e9 Flashcards Anki Coups de pouce Laisser la souris\/taper sur le texte pour l&rsquo;afficher. Exercice 1 Quelles amplitudes complexes sont en fait r\u00e9elles si on prend commet origine des phases ? \u00c9crire la loi des mailles en utilisant les&hellip;<\/p>\n<p class=\"more-link-p\"><a class=\"more-link\" href=\"https:\/\/www.cpge-brizeux.fr\/wordpress\/psi\/physchim-psi-2526\/conversion-de-puissance-3-conversion-electro-magneto-mecanique-2.html\">Read more &rarr;<\/a><\/p>\n","protected":false},"author":26,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[430],"tags":[],"class_list":["post-37253","post","type-post","status-publish","format-standard","hentry","category-physchim-psi-2526"],"_links":{"self":[{"href":"https:\/\/www.cpge-brizeux.fr\/wordpress\/wp-json\/wp\/v2\/posts\/37253","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.cpge-brizeux.fr\/wordpress\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.cpge-brizeux.fr\/wordpress\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.cpge-brizeux.fr\/wordpress\/wp-json\/wp\/v2\/users\/26"}],"replies":[{"embeddable":true,"href":"https:\/\/www.cpge-brizeux.fr\/wordpress\/wp-json\/wp\/v2\/comments?post=37253"}],"version-history":[{"count":2,"href":"https:\/\/www.cpge-brizeux.fr\/wordpress\/wp-json\/wp\/v2\/posts\/37253\/revisions"}],"predecessor-version":[{"id":37282,"href":"https:\/\/www.cpge-brizeux.fr\/wordpress\/wp-json\/wp\/v2\/posts\/37253\/revisions\/37282"}],"wp:attachment":[{"href":"https:\/\/www.cpge-brizeux.fr\/wordpress\/wp-json\/wp\/v2\/media?parent=37253"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.cpge-brizeux.fr\/wordpress\/wp-json\/wp\/v2\/categories?post=37253"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.cpge-brizeux.fr\/wordpress\/wp-json\/wp\/v2\/tags?post=37253"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}