{"id":37681,"date":"2026-01-04T23:49:34","date_gmt":"2026-01-04T21:49:34","guid":{"rendered":"https:\/\/www.cpge-brizeux.fr\/wordpress\/non-classe\/phenomenes-de-transport-4-fluide-en-ecoulement-2.html"},"modified":"2026-01-04T23:49:34","modified_gmt":"2026-01-04T21:49:34","slug":"phenomenes-de-transport-4-fluide-en-ecoulement-2","status":"publish","type":"post","link":"https:\/\/www.cpge-brizeux.fr\/wordpress\/psi\/physchim-psi-2526\/phenomenes-de-transport-4-fluide-en-ecoulement-2.html","title":{"rendered":"Ph\u00e9nom\u00e8nes de transport 4 : Fluide en \u00e9coulement"},"content":{"rendered":"<h2>T\u00e9l\u00e9chargements<\/h2>\n<p><a href='https:\/\/www.cpge-brizeux.fr\/wordpress\/wp-content\/uploads\/phenomenes-de-transport-4-fluide-en-ecoulement-poly.pdf'>Polycopi\u00e9<\/a><\/p>\n<p><a href='https:\/\/www.cpge-brizeux.fr\/wordpress\/wp-content\/uploads\/phenomenes-de-transport-4-fluide-en-ecoulement-flashcards.apkg'>Flashcards Anki<\/a><\/p>\n<h2>Coups de pouce<\/h2>\n<p>Laisser la souris\/taper sur le texte pour l&rsquo;afficher.<\/p>\n<div class='coups-de-pouce'>\n<h5>Exercice 1<\/h5>\n<ol>\n<li>\n<ul>\n<li>\n    Relier la masse volumique \u00e0 la pression gr\u00e2ce \u00e0 l\u2019\u00e9quation d\u2019\u00e9tat des gaz parfaits.\n  <\/li>\n<li>\n    R\u00e9soudre l\u2019\u00e9quation fondamentale de l\u2019hydrostatique.\n  <\/li>\n<\/ul>\n<\/li>\n<li>\n<ul>\n<li>\n    On consid\u00e8re un cylindre de section <span style=\"display: inline-block\"><svg class=\"typst-frame\" style=\"overflow: visible; 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Exprimer la masse contenue dans ce cylindre comme une int\u00e9grale.\n  <\/li>\n<li>\n    On souhaite montrer que la masse contenue dans un cylindre de hauteur <span style=\"display: inline-block\"><svg class=\"typst-frame\" style=\"overflow: visible; width: 2.527667em; height: 0.683em;\" viewBox=\"0 0 27.804337 7.513000000000001\" width=\"27.804337pt\" height=\"7.513000000000001pt\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" xmlns:xlink=\"http:\/\/www.w3.org\/1999\/xlink\" xmlns:h5=\"http:\/\/www.w3.org\/1999\/xhtml\"><g><g class=\"typst-text\" transform=\"matrix(1 0 0 -1 0 7.513000000000001)\"><use xlink:href=\"#gFA18BF337B40C3FFB73D10D49D4EB853\" x=\"0\" y=\"0\" fill=\"#000000\" fill-rule=\"nonzero\"\/><\/g><g class=\"typst-text\" transform=\"matrix(1 0 0 -1 5.5 7.513000000000001)\"><use xlink:href=\"#gD196D1EC340CB2D2C631870E428E313E\" x=\"0\" y=\"0\" fill=\"#000000\" fill-rule=\"nonzero\"\/><\/g><g class=\"typst-text\" transform=\"matrix(1 0 0 -1 12.833337 7.513000000000001)\"><use 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infinie.\n  <\/li>\n<\/ul>\n<\/li>\n<li>\n<ul>\n<\/ul>\n<\/li>\n<li>\n<ul>\n<li>\n    Utiliser la loi de Laplace et l\u2019\u00e9quation d\u2019\u00e9tat des gaz parfaits.\n  <\/li>\n<\/ul>\n<\/li>\n<li>\n<ul>\n<li>\n    Exprimer <span style=\"display: inline-block\"><svg class=\"typst-frame\" style=\"overflow: visible; width: 0.732em; height: 0.683em;\" viewBox=\"0 0 8.052 7.513000000000001\" width=\"8.052pt\" height=\"7.513000000000001pt\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" xmlns:xlink=\"http:\/\/www.w3.org\/1999\/xlink\" xmlns:h5=\"http:\/\/www.w3.org\/1999\/xhtml\"><g><g class=\"typst-text\" transform=\"matrix(1 0 0 -1 0 7.513000000000001)\"><use xlink:href=\"#gB5F81477AB34379BE026440219E33852\" x=\"0\" y=\"0\" fill=\"#000000\" fill-rule=\"nonzero\"\/><\/g><\/g><defs id=\"glyph\"><symbol id=\"gB5F81477AB34379BE026440219E33852\" overflow=\"visible\"><path d=\"M 0 0m 3.784 6.941 c 0 -0.032999992 -0.010999918 -0.11000013 -0.04399991 -0.21999979 l -1.4519999 -5.808 c -0.04400015 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0.033 l 0.704 -0.011 c 0.12100005 0 0.5610001 -0.022 0.704 -0.022 c 0.17600012 0 0.26400018 0.088 0.26400018 0.264 c 0 0.110000014 -0.12100005 0.16499999 -0.35200024 0.16499999 c -0.43999982 0 -0.65999985 0.044 -0.65999985 0.14300004 c 0 0 0.010999918 0.032999992 0.032999992 0.176 l 0.6600001 2.684 h 1.8149998 c 0.71500015 0 1.3969998 0.22000003 2.0349998 0.6489999 c 0.71500015 0.47300005 1.0669999 1.0560002 1.0669999 1.7490001 c 0 1.0890002 -1.0339999 1.6830001 -2.1889997 1.6830001 Z m -0.34100008 -0.4289999 c 0.95700026 0 1.4299998 -0.32999992 1.4299998 -0.99000025 c 0 -0.6159997 -0.3079996 -1.441 -0.62699986 -1.7269998 c -0.41799974 -0.37400007 -0.96799994 -0.5610001 -1.6500001 -0.5610001 h -1.4739997 l 0.7260001 2.904 c 0.08799982 0.37400007 0.08799982 0.37400007 0.5499997 0.37400007 Z \"\/><\/symbol><\/defs><\/svg><\/span> et diff\u00e9rentier l\u2019expression obtenue.\n  <\/li>\n<\/ul>\n<\/li>\n<li>\n<ul>\n<li>\n    Utiliser la question pr\u00e9c\u00e9dente et l\u2019\u00e9quation fondamentale de l\u2019hydrostatique.\n  <\/li>\n<\/ul>\n<\/li>\n<li>\n<ul>\n<\/ul>\n<\/li>\n<\/ol>\n<h5>Exercice 2<\/h5>\n<ol>\n<li>\n<ul>\n<li>\n    Calculer la composante normale de la r\u00e9action puis utiliser la loi de Coulomb.\n  <\/li>\n<li>\n    Projeter le th\u00e9or\u00e8me de la r\u00e9sultante cin\u00e9tique sur l\u2019axe verticale pour relier la r\u00e9action normale au poids.\n  <\/li>\n<\/ul>\n<\/li>\n<li>\n<ul>\n<li>\n    R\u00e9soudre la projection sur l\u2019axe horizontal du th\u00e9or\u00e8me de la r\u00e9sultante cin\u00e9tique.\n  <\/li>\n<li>\n    Quel est le temps d\u2019arr\u00eat, c\u2019est-\u00e0-dire le temps auquel la vitesse est nulle.\n  <\/li>\n<li>\n    La distance d\u2019arr\u00eat correspond \u00e0 la position du solide au temps d\u2019arr\u00eat.\n  <\/li>\n<\/ul>\n<\/li>\n<li>\n<ul>\n<\/ul>\n<\/li>\n<li>\n<ul>\n<li>\n    Utiliser un argument d\u2019invariance.\n  <\/li>\n<li>\n    Que signifie l\u2019expression de l\u2019\u00e9nonc\u00e9 \u201con n\u00e9glige les effets de bord\u201d ?\n  <\/li>\n<\/ul>\n<\/li>\n<li>\n<ul>\n<li>\n    Utiliser la condition d\u2019adh\u00e9rence en <span style=\"display: inline-block\"><svg class=\"typst-frame\" style=\"overflow: visible; width: 2.3285555555555555em; height: 0.683em;\" viewBox=\"0 0 25.61411111111111 7.513000000000001\" width=\"25.61411111111111pt\" height=\"7.513000000000001pt\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" xmlns:xlink=\"http:\/\/www.w3.org\/1999\/xlink\" xmlns:h5=\"http:\/\/www.w3.org\/1999\/xhtml\"><g><g class=\"typst-text\" transform=\"matrix(1 0 0 -1 0 7.513000000000001)\"><use xlink:href=\"#g25324936E00E6CB0B285DCF1381CA276\" x=\"0\" y=\"0\" fill=\"#000000\" fill-rule=\"nonzero\"\/><\/g><g class=\"typst-text\" transform=\"matrix(1 0 0 -1 8.500555555555556 7.513000000000001)\"><use xlink:href=\"#g8E79D971ED2DF2360F7CF2540389221\" x=\"0\" y=\"0\" fill=\"#000000\" fill-rule=\"nonzero\"\/><\/g><g class=\"typst-text\" 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-0.05499983 0.18700004 -0.17600012 0.18700004 c -0.05499983 0 -0.11000013 -0.04400003 -0.17600012 -0.13200009 c -0.36299992 -0.48399997 -0.8139999 -0.79199994 -1.3309999 -0.92399997 c -0.34099984 -0.087999985 -0.59399986 -0.13199998 -0.7809999 -0.13199998 c -0.6270001 0 -0.90200007 0.594 -0.90200007 1.2210001 Z m 2.7610002 2.486 c 0 -0.7260001 -0.704 -1.089 -2.123 -1.089 h -0.3850001 c 0.20899999 0.7260001 0.5170001 1.21 0.93500006 1.441 c 0.32999992 0.1869998 0.605 0.28599977 0.82500005 0.28599977 c 0.3959999 0 0.7479999 -0.24199963 0.7479999 -0.6379998 Z \"\/><\/symbol><\/defs><\/svg><\/span>.\n  <\/li>\n<\/ul>\n<\/li>\n<li>\n<ul>\n<\/ul>\n<\/li>\n<li>\n<ul>\n<li>\n    La force exerc\u00e9e sur le pav\u00e9 et l\u2019oppos\u00e9 de la force exerc\u00e9e par le pav\u00e9 sur la couche sup\u00e9rieure de fluide.\n  <\/li>\n<\/ul>\n<\/li>\n<li>\n<ul>\n<li>\n    R\u00e9soudre la projection sur l\u2019axe horizontal du th\u00e9or\u00e8me de la r\u00e9sultante cin\u00e9tique.\n  <\/li>\n<li>\n    La distance d\u2019arr\u00eat peut \u00eatre d\u00e9finie comme la valeur maximale atteinte par la position.\n  <\/li>\n<\/ul>\n<\/li>\n<\/ol>\n<h5>Exercice 3<\/h5>\n<ol>\n<li>\n<ul>\n<li>\n    Appliquer la loi de la quantit\u00e9 de mouvement \u00e0 une particule de fluide.\n  <\/li>\n<li>\n    Comment s\u2019exprime l\u2019acc\u00e9l\u00e9ration d\u2019une particule de fluide \u00e0 partir du champ de vitesse ?\n  <\/li>\n<\/ul>\n<\/li>\n<li>\n<ul>\n<li>\n    \u00c9crire la condition d\u2019adh\u00e9rence sur les 4 parois de la conduite.\n  <\/li>\n<\/ul>\n<\/li>\n<li>\n<ul>\n<li>\n    En n\u00e9gligeant les effets de bord, quelles sont les invariances du probl\u00e8me ?\n  <\/li>\n<li>\n    Utiliser le principe de Curie.\n  <\/li>\n<\/ul>\n<\/li>\n<li>\n<ul>\n<li>\n    Simplifier l\u2019\u00e9quation aux d\u00e9riv\u00e9es partielles v\u00e9rifi\u00e9e par le champ de vitesse en utilisant la question pr\u00e9c\u00e9dente.\n  <\/li>\n<li>\n    Primitiver deux fois 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On introduira deux constantes.\n  <\/li>\n<li>\n    Pour d\u00e9terminer les constantes, on utilise les conditions aux limites en <span style=\"display: inline-block\"><svg class=\"typst-frame\" style=\"overflow: visible; width: 3.204855555555555em; height: 0.683em;\" viewBox=\"0 0 35.253411111111106 7.513000000000001\" width=\"35.253411111111106pt\" height=\"7.513000000000001pt\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" xmlns:xlink=\"http:\/\/www.w3.org\/1999\/xlink\" xmlns:h5=\"http:\/\/www.w3.org\/1999\/xhtml\"><g><g class=\"typst-text\" transform=\"matrix(1 0 0 -1 0 7.513000000000001)\"><use xlink:href=\"#g25324936E00E6CB0B285DCF1381CA276\" x=\"0\" y=\"0\" fill=\"#000000\" fill-rule=\"nonzero\"\/><\/g><g class=\"typst-text\" transform=\"matrix(1 0 0 -1 8.500555555555556 7.513000000000001)\"><use xlink:href=\"#g8E79D971ED2DF2360F7CF2540389221\" x=\"0\" y=\"0\" fill=\"#000000\" fill-rule=\"nonzero\"\/><\/g><g class=\"typst-text\" transform=\"matrix(1 0 0 -1 20.11411111111111 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0.17600012 0 0.26399994 0.08800006 0.26399994 0.26400006 c 0 0.13199997 -0.12099981 0.25299996 -0.26399994 0.25299996 Z \"\/><\/symbol><symbol id=\"gA3F7788217605CF2A7DF8A5CB2EE350D\" overflow=\"visible\"><path d=\"M 0 0m 3.6498 0.9702 c -0.046200037 0 -0.092400074 -0.030799985 -0.13860011 -0.092400014 c -0.39269996 -0.4543 -0.924 -0.6853 -1.5862 -0.6853 c -0.4850999 0 -0.7314999 0.2926 -0.7314999 0.88549995 c 0 0.16170001 0.030799985 0.37730002 0.08469999 0.64680004 h 0.45429993 c 1.2705001 0 1.9096001 0.3233999 1.9096001 0.9778999 c 0 0.45430017 -0.47740006 0.6930001 -0.9625001 0.6930001 c -0.32340002 0 -0.64680004 -0.0769999 -0.97020006 -0.22329998 c -0.6236999 -0.28489995 -1.1934999 -0.9470999 -1.1934999 -1.7941 c 0 -0.84699994 0.5467 -1.4553 1.3937 -1.4553 c 0.47740006 0 0.88549995 0.0924 1.2242999 0.27719998 c 0.17709994 0.10010001 0.67760015 0.42350003 0.67760015 0.6083 c 0 0.069299996 -0.092400074 0.16170001 -0.16170001 0.16170001 Z m -0.3927002 1.7324998 c 0 -0.46969986 -0.52359986 -0.7083999 -1.5707998 -0.7083999 h -0.3311 c 0.14629996 0.4850999 0.3772999 0.80849993 0.70070004 0.9548 c 0.25409985 0.11549997 0.4619999 0.17709994 0.6236999 0.17709994 c 0.29259992 0 0.57749987 -0.14630008 0.57749987 -0.42350006 Z \"\/><\/symbol><symbol id=\"g35089A96F4517D19458AAA3BAF36FB65\" overflow=\"visible\"><path d=\"M 0 0m 0.9163 3.2648 c 0.24639994 0 0.43119997 0.18479991 0.43119997 0.43120003 c 0 0.27719998 -0.14629996 0.42350006 -0.43119997 0.43120003 c 0.16940004 0.36189985 0.5544 0.6545 1.0548999 0.6545 c 0.6775999 0 1.1242001 -0.50820017 1.1242001 -1.1858001 c 0 -0.36960006 -0.13090014 -0.7238002 -0.40040016 -1.0703001 c -0.1308999 -0.17709994 -0.23099995 -0.30029988 -0.30029988 -0.36960006 l -1.8249 -1.8094999 c -0.10010001 -0.092400014 -0.08470002 -0.1155 -0.08470002 -0.3465 h 3.1724 l 0.23869991 1.4476 h -0.32340002 c -0.053900003 -0.4081 -0.11549997 -0.64680004 -0.18479991 -0.7007 c -0.03850007 -0.023100019 -0.27719998 -0.03850001 -0.7314999 -0.03850001 h -1.3090001 c 0.5159 0.45429993 0.9933001 0.86239994 1.4476 1.2243 c 0.34649992 0.2694999 0.59290004 0.50820005 0.7469001 0.71609986 c 0.23099995 0.30030012 0.34649992 0.6160002 0.34649992 0.94710016 c 0 0.47739983 -0.18479991 0.8547001 -0.56209993 1.1318998 c -0.3311 0.25409985 -0.7469001 0.38500023 -1.2397001 0.38500023 c -0.42349994 0 -0.7853999 -0.12319994 -1.1011 -0.3696003 c -0.3311 -0.26949978 -0.50049996 -0.60829973 -0.50049996 -1.0240998 c 0 -0.26180005 0.19250003 -0.45429993 0.4312 -0.45429993 Z \"\/><\/symbol><\/defs><\/svg><\/span>.\n  <\/li>\n<\/ul>\n<\/li>\n<li>\n<ul>\n<li>\n    Quelle relation relie le champ de vitesse au d\u00e9bit volumique ?\n  <\/li>\n<\/ul>\n<\/li>\n<li>\n<ul>\n<li>\n    Relier la diff\u00e9rence de pression entre les deux extr\u00e9mit\u00e9s de la conduite \u00e0 la d\u00e9riv\u00e9e de la pression (l\u2019\u00e9nonc\u00e9 pr\u00e9cise que le gradient de pression est uniforme).\n  <\/li>\n<\/ul>\n<\/li>\n<\/ol>\n<h5>Exercice 4<\/h5>\n<ol>\n<li>\n<ul>\n<li>\n    R\u00e9soudre l\u2019\u00e9quation fondamentale de l\u2019hydrostatique pour un fluide incompressible.\n  <\/li>\n<\/ul>\n<\/li>\n<li>\n<ul>\n<li>\n    Utiliser la loi de Hagen-Poiseuille.\n  <\/li>\n<\/ul>\n<\/li>\n<li>\n<ul>\n<\/ul>\n<\/li>\n<li>\n<ul>\n<li>\n    La vitesse intervient dans le nombre de Reynolds mais aussi dans le coefficient de perte de charge.\n  <\/li>\n<li>\n    Raisonner \u00e0 nombre de Reynolds fix\u00e9.\n  <\/li>\n<\/ul>\n<\/li>\n<\/ol>\n<h5>Exercice 5<\/h5>\n<ol>\n<li>\n<ul>\n<\/ul>\n<\/li>\n<\/ol>\n<h5>Exercice 6<\/h5>\n<ol>\n<li>\n<ul>\n<li>\n    Calculer le nombre de Reynolds dans chacune des deux conduites.\n  <\/li>\n<li>\n    \u00c0 l\u2019aide du diagramme de Moody, calculer le coefficient de perte de charge dans chacune des deux conduites.\n  <\/li>\n<li>\n    Calculer la chute de pression dans chacune des deux conduites.\n  <\/li>\n<li>\n    Quelle relation relie la chute de pression totale aux chutes de pression dans chacune des deux conduites.\n  <\/li>\n<\/ul>\n<\/li>\n<\/ol>\n<h5>Exercice 7<\/h5>\n<ol>\n<li>\n<ul>\n<li>\n    Quelles sont les 3 forces qui s\u2019exercent sur la bille ?\n  <\/li>\n<li>\n    Appliquer le th\u00e9or\u00e8me de la r\u00e9sultante cin\u00e9tique \u00e0 la bille.\n  <\/li>\n<\/ul>\n<\/li>\n<li>\n<ul>\n<\/ul>\n<\/li>\n<li>\n<ul>\n<li>\n    Quelle est la solution particuli\u00e8re de l\u2019\u00e9quation diff\u00e9rentielle ?\n  <\/li>\n<li>\n    Exprimer la masse de la bille en fonction de <span style=\"display: inline-block\"><svg class=\"typst-frame\" style=\"overflow: visible; width: 0.53em; height: 0.683em;\" viewBox=\"0 0 5.830000000000001 7.513000000000001\" width=\"5.830000000000001pt\" height=\"7.513000000000001pt\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" xmlns:xlink=\"http:\/\/www.w3.org\/1999\/xlink\" xmlns:h5=\"http:\/\/www.w3.org\/1999\/xhtml\"><g><g class=\"typst-text\" transform=\"matrix(1 0 0 -1 0 7.513000000000001)\"><use xlink:href=\"#gE0729373B86AE8EE0B50DB001BC424AA\" x=\"0\" y=\"0\" fill=\"#000000\" fill-rule=\"nonzero\"\/><\/g><\/g><defs id=\"glyph\"><symbol id=\"gE0729373B86AE8EE0B50DB001BC424AA\" overflow=\"visible\"><path d=\"M 0 0m 3.971 4.862 c -1.243 0 -2.277 -1.342 -2.552 -2.442 l -1.056 -4.2790003 c -0.022000015 -0.08800006 -0.033000022 -0.14300013 -0.033000022 -0.17600012 c 0 -0.23099995 0.110000014 -0.34099984 0.34100002 -0.34099984 c 0.16499996 0 0.30799997 0.08799982 0.41799998 0.25300002 l 0.671 2.629 c 0.25300002 -0.429 0.605 -0.649 1.056 -0.649 c 0.7260001 0 1.3639998 0.352 1.9250002 1.067 c 0.5169997 0.671 0.78099966 1.3859999 0.78099966 2.123 c 0 1.0009999 -0.5829997 1.815 -1.5509999 1.815 Z m -0.022000074 -0.32999992 c 0.47300005 0 0.704 -0.34100008 0.704 -1.023 c 0 -0.29700017 -0.065999985 -0.68200016 -0.1869998 -1.177 c -0.2420001 -0.93500006 -0.5830002 -1.562 -1.0120001 -1.892 c -0.23099995 -0.176 -0.44000006 -0.264 -0.6489999 -0.264 c -0.20900011 0 -0.39600015 0.07699999 -0.53900003 0.22 c -0.23099995 0.23099998 -0.34100008 0.47300002 -0.34100008 0.704 c 0.011000037 0.07700002 0.032999992 0.20899999 0.07700014 0.39600003 c 0.25299978 1.0449998 0.4729998 1.7159998 0.6489999 2.024 c 0.385 0.671 0.8139999 1.0120001 1.2979999 1.0120001 Z \"\/><\/symbol><\/defs><\/svg><\/span> et de <span style=\"display: inline-block\"><svg class=\"typst-frame\" style=\"overflow: visible; width: 0.783em; height: 0.683em;\" viewBox=\"0 0 8.613000000000001 7.513000000000001\" width=\"8.613000000000001pt\" height=\"7.513000000000001pt\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" xmlns:xlink=\"http:\/\/www.w3.org\/1999\/xlink\" xmlns:h5=\"http:\/\/www.w3.org\/1999\/xhtml\"><g><g class=\"typst-text\" transform=\"matrix(1 0 0 -1 0 7.513000000000001)\"><use xlink:href=\"#g62B8E2FEAE3B13478FE2C59D5E274677\" x=\"0\" y=\"0\" fill=\"#000000\" fill-rule=\"nonzero\"\/><\/g><\/g><defs id=\"glyph\"><symbol id=\"g62B8E2FEAE3B13478FE2C59D5E274677\" overflow=\"visible\"><path d=\"M 0 0m 8.129 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0.32999992 -0.38500023 0.32999992 -0.72599983 c 0 -0.22000027 -0.043999672 -0.47300005 -0.14299965 -0.77000046 c -0.2970004 -0.90199995 -1.0450001 -1.3529997 -2.244 -1.3529997 h -1.1660001 l 0.6930001 2.783 c 0.05499983 0.23099995 0.14299965 0.35199976 0.26399994 0.36299992 c 0.05499983 0.011000156 0.2750001 0.011000156 0.65999985 0.011000156 c 0.71500015 0 1.1329999 -0.022000313 1.606 -0.3080001 Z \"\/><\/symbol><\/defs><\/svg><\/span>.\n  <\/li>\n<\/ul>\n<\/li>\n<li>\n<ul>\n<li>\n    En comparant <span style=\"display: inline-block\"><svg class=\"typst-frame\" style=\"overflow: visible; width: 1.060667em; height: 0.683em;\" viewBox=\"0 0 11.667337000000002 7.513000000000001\" width=\"11.667337000000002pt\" height=\"7.513000000000001pt\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" xmlns:xlink=\"http:\/\/www.w3.org\/1999\/xlink\" xmlns:h5=\"http:\/\/www.w3.org\/1999\/xhtml\"><g><g class=\"typst-text\" transform=\"matrix(1 0 0 -1 0 7.513000000000001)\"><use 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-0.022000074 0.32999992 -0.3080001 0.32999992 Z \"\/><\/symbol><symbol id=\"gE0744868EB0FDA0E3096B7009AA205B8\" overflow=\"visible\"><path d=\"M 0 0m 3.96 1.43 c 0 0.8360001 -0.572 1.364 -1.7050002 1.584 c -0.51699984 0.09899998 -0.8469999 0.22000003 -1.0229999 0.34100008 c -0.176 0.12100005 -0.264 0.29699993 -0.264 0.50600004 c 0 0.5169997 0.38500005 0.77 1.155 0.77 c 0.74800014 0 1.155 -0.41800022 1.21 -1.2650001 c 0.010999918 -0.08800006 0.065999985 -0.13199997 0.17600012 -0.13199997 c 0.12099981 0 0.18700004 0.09899998 0.18700004 0.29699993 v 1.089 c 0 0.20900011 -0.055000067 0.3080001 -0.1650002 0.3080001 c -0.12099981 0 -0.286 -0.19799995 -0.3959999 -0.28599977 c -0.2750001 0.1869998 -0.61599994 0.28599977 -1.0120001 0.28599977 c -0.97899985 0 -1.7599999 -0.44000006 -1.7599999 -1.375 c 0 -0.37400007 0.15400001 -0.6930001 0.47299996 -0.9460001 c 0.385 -0.31899977 0.748 -0.385 1.441 -0.5059998 c 0.71500015 -0.14300013 1.0780001 -0.46200013 1.0780001 -0.957 c 0 -0.62700003 -0.385 -0.94600004 -1.1660001 -0.94600004 c -0.75899994 0 -1.2429999 0.506 -1.4519999 1.5070001 c -0.032999992 0.143 -0.088 0.21999991 -0.18699998 0.21999991 c -0.12100002 0 -0.187 -0.110000014 -0.187 -0.319 v -1.4189999 c 0 -0.209 0.054999977 -0.308 0.16499999 -0.308 c 0.032999992 0 0.088 0.033 0.176 0.11 c 0.19800001 0.176 0.110000014 0.143 0.30799997 0.341 c 0.319 -0.297 0.71500003 -0.45099998 1.1769999 -0.45099998 c 1.0450001 0 1.7710001 0.539 1.7710001 1.551 Z \"\/><\/symbol><\/defs><\/svg><\/span> et <span style=\"display: inline-block\"><svg class=\"typst-frame\" style=\"overflow: visible; width: 0.539em; height: 0.683em;\" viewBox=\"0 0 5.929 7.513000000000001\" width=\"5.929pt\" height=\"7.513000000000001pt\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" xmlns:xlink=\"http:\/\/www.w3.org\/1999\/xlink\" xmlns:h5=\"http:\/\/www.w3.org\/1999\/xhtml\"><g><g class=\"typst-text\" transform=\"matrix(1 0 0 -1 0 7.513000000000001)\"><use xlink:href=\"#gC2CF87D5473896407F03A19513AEB661\" x=\"0\" y=\"0\" fill=\"#000000\" fill-rule=\"nonzero\"\/><\/g><\/g><defs id=\"glyph\"><symbol id=\"gC2CF87D5473896407F03A19513AEB661\" overflow=\"visible\"><path d=\"M 0 0m 5.148 4.741 h -3.0359998 c -0.58299994 0 -1.111 -0.37400007 -1.595 -1.1110003 c -0.143 -0.21999979 -0.22000003 -0.36299992 -0.22000003 -0.41799998 c 0.032999992 -0.08799982 0.044 -0.14299989 0.176 -0.14299989 c 0.07700002 0 0.143 0.04399991 0.20899999 0.14299989 c 0.35200006 0.53900003 0.792 0.8140001 1.3310001 0.8140001 h 0.8469999 l -1.045 -3.41 c -0.0769999 -0.24199998 -0.109999895 -0.385 -0.109999895 -0.41799998 c 0 -0.22 0.12099993 -0.32999998 0.35199988 -0.32999998 c 0.12100005 0 0.23100019 0.033 0.29700017 0.099 c 0.14299989 0.132 0.1539998 0.16499999 0.19799995 0.396 l 0.7149999 3.663 h 1.7819998 c 0.38500023 0 0.572 0.13199997 0.572 0.40700006 c 0 0.25299978 -0.19799995 0.3080001 -0.47300005 0.3080001 Z \"\/><\/symbol><\/defs><\/svg><\/span>, dans quel r\u00e9gime se trouve-t-on ? Quelle est l\u2019expression de la vitesse dans ce r\u00e9gime ?\n  <\/li>\n<\/ul>\n<\/li>\n<li>\n<ul>\n<li>\n    Le nombre de Reynolds croit-il ou d\u00e9croit-il avec <span style=\"display: inline-block\"><svg class=\"typst-frame\" style=\"overflow: visible; width: 0.4640000000000001em; height: 0.683em;\" viewBox=\"0 0 5.104000000000001 7.513000000000001\" width=\"5.104000000000001pt\" height=\"7.513000000000001pt\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" xmlns:xlink=\"http:\/\/www.w3.org\/1999\/xlink\" xmlns:h5=\"http:\/\/www.w3.org\/1999\/xhtml\"><g><g class=\"typst-text\" transform=\"matrix(1 0 0 -1 0 7.513000000000001)\"><use xlink:href=\"#g1138D9F2954336FB24DB0605F9A73B67\" x=\"0\" y=\"0\" fill=\"#000000\" fill-rule=\"nonzero\"\/><\/g><\/g><defs id=\"glyph\"><symbol id=\"g1138D9F2954336FB24DB0605F9A73B67\" overflow=\"visible\"><path d=\"M 0 0m 4.796 4.114 c 0 0.46200037 -0.4510002 0.74800014 -0.93499994 0.74800014 c -0.53900003 0 -0.99 -0.25299978 -1.3640001 -0.77 c -0.109999895 0.4289999 -0.48399997 0.77 -1.0009999 0.77 c -0.4510001 0 -0.7810001 -0.35200024 -1.0120001 -1.0669999 c -0.109999985 -0.36300015 -0.16499999 -0.572 -0.16499999 -0.638 c 0 -0.09899998 0.055000007 -0.15400004 0.176 -0.15400004 c 0.055000007 0 0.088 0.010999918 0.12099999 0.032999992 c 0.055000007 0.09899998 0.088 0.17599988 0.09899998 0.25300002 c 0.19800001 0.83599997 0.45100003 1.2539997 0.74799997 1.2539997 c 0.18700004 0 0.286 -0.1539998 0.286 -0.4619999 c 0 -0.14299989 -0.054999948 -0.43999982 -0.16499996 -0.8909998 l -0.627 -2.497 c -0.032999992 -0.143 -0.09900004 -0.42900002 -0.09900004 -0.48400003 c 0 -0.22 0.12099999 -0.32999998 0.35200006 -0.32999998 c 0.21999991 0 0.36299992 0.11 0.43999994 0.32999998 l 0.20899999 0.79200006 c 0.12100005 0.47299993 0.19799995 0.7809999 0.23099995 0.9239999 l 0.34100008 1.408 c 0.022000074 0.08800006 0.109999895 0.23099995 0.25300002 0.44000006 c 0.29699993 0.41799998 0.638 0.76999974 1.177 0.76999974 c 0.13199997 0 0.2420001 -0.021999836 0.34100008 -0.076999664 c -0.33000016 -0.09899998 -0.49500012 -0.3080001 -0.49500012 -0.605 c 0 -0.286 0.15400004 -0.42900014 0.45099998 -0.42900014 c 0.36299992 0 0.638 0.319 0.638 0.6819999 Z \"\/><\/symbol><\/defs><\/svg><\/span> ?\n  <\/li>\n<\/ul>\n<\/li>\n<\/ol>\n<h5>Exercice 8<\/h5>\n<ol>\n<li>\n<ul>\n<li>\n    Que vaut le ma\u00eetre couple pour une sph\u00e8re de rayon <span style=\"display: inline-block\"><svg class=\"typst-frame\" style=\"overflow: visible; width: 0.783em; height: 0.683em;\" viewBox=\"0 0 8.613000000000001 7.513000000000001\" width=\"8.613000000000001pt\" height=\"7.513000000000001pt\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" xmlns:xlink=\"http:\/\/www.w3.org\/1999\/xlink\" xmlns:h5=\"http:\/\/www.w3.org\/1999\/xhtml\"><g><g class=\"typst-text\" transform=\"matrix(1 0 0 -1 0 7.513000000000001)\"><use xlink:href=\"#g62B8E2FEAE3B13478FE2C59D5E274677\" x=\"0\" y=\"0\" fill=\"#000000\" fill-rule=\"nonzero\"\/><\/g><\/g><defs id=\"glyph\"><symbol id=\"g62B8E2FEAE3B13478FE2C59D5E274677\" overflow=\"visible\"><path d=\"M 0 0m 8.129 5.841 c 0 0.5609999 -0.28599977 0.9899998 -0.84699965 1.2979999 c -0.4510002 0.25300026 -0.99000025 0.37400007 -1.5950003 0.37400007 h -3.1019998 c -0.25300002 0 -0.36300015 -0.011000156 -0.36300015 -0.26399994 c 0 -0.07700014 0.032999992 -0.13199997 0.099000216 -0.14300013 c 0.109999895 -0.011000156 0.19799995 -0.021999836 0.25299978 -0.021999836 c 0.33000016 -0.011000156 0.5170002 -0.032999992 0.572 -0.04400015 c 0.055000067 -0.011000156 0.08800006 -0.04400015 0.08800006 -0.09899998 c 0 -0.021999836 -0.010999918 -0.08799982 -0.04399991 -0.19799995 l -1.452 -5.841 c -0.055000067 -0.24200004 -0.16500008 -0.39600003 -0.33000004 -0.451 c -0.07700002 -0.022000015 -0.27499998 -0.033000022 -0.616 -0.033000022 c -0.24199998 0 -0.341 -0.010999978 -0.341 -0.253 c 0 -0.12099999 0.066000015 -0.176 0.19799998 -0.16499999 l 1.3640001 0.033 l 1.3859999 -0.033 c 0.17600012 -0.011 0.26399994 0.088 0.26399994 0.253 c 0 0.110000014 -0.12099981 0.16499999 -0.352 0.16499999 c -0.43999982 0 -0.65999985 0.055000007 -0.65999985 0.15400004 c 0 0 0.010999918 0.021999955 0.032999992 0.176 l 0.704 2.849 h 1.2649999 c 0.7590003 0 1.144 -0.319 1.144 -0.94599986 c 0 -0.09899998 -0.05499983 -0.34100008 -0.1539998 -0.737 c -0.12100029 -0.462 -0.17600012 -0.77 -0.17600012 -0.93500006 c 0 -0.83599997 0.64900017 -1.221 1.4850001 -1.221 c 0.3079996 0 0.605 0.143 0.90199995 0.41799998 c 0.29699993 0.275 0.4510002 0.572 0.4510002 0.88 c 0 0.110000014 -0.055000305 0.16499996 -0.1760006 0.16499996 c -0.076999664 0 -0.14299965 -0.054999948 -0.17599964 -0.176 c -0.12100029 -0.34099996 -0.2750001 -0.594 -0.4510002 -0.737 c -0.17600012 -0.143 -0.34100008 -0.22 -0.50600004 -0.22 c -0.25299978 0 -0.38499975 0.20899999 -0.38499975 0.616 c 0 0.264 0.032999992 0.671 0.11000013 1.232 c 0.032999992 0.23100007 0.043999672 0.39600003 0.043999672 0.5170001 c 0 0.58299994 -0.3080001 1.0119998 -0.9239998 1.276 c 1.0339999 0.25299978 2.2879996 0.9899998 2.2879996 2.112 Z m -1.4299998 0.93499994 c 0.22000027 -0.14300013 0.32999992 -0.38500023 0.32999992 -0.72599983 c 0 -0.22000027 -0.043999672 -0.47300005 -0.14299965 -0.77000046 c -0.2970004 -0.90199995 -1.0450001 -1.3529997 -2.244 -1.3529997 h -1.1660001 l 0.6930001 2.783 c 0.05499983 0.23099995 0.14299965 0.35199976 0.26399994 0.36299992 c 0.05499983 0.011000156 0.2750001 0.011000156 0.65999985 0.011000156 c 0.71500015 0 1.1329999 -0.022000313 1.606 -0.3080001 Z \"\/><\/symbol><\/defs><\/svg><\/span> ?\n  <\/li>\n<\/ul>\n<\/li>\n<li>\n<ul>\n<li>\n    Faire le bilan des forces agissant sur la bille.\n  <\/li>\n<\/ul>\n<\/li>\n<li>\n<ul>\n<li>\n    Comme se simplifie l\u2019\u00e9quation diff\u00e9rentielle en r\u00e9gime stationnaire ?\n  <\/li>\n<\/ul>\n<\/li>\n<li>\n<ul>\n<li>\n    Isoler la d\u00e9riv\u00e9e de la vitesse dans l\u2019\u00e9quation diff\u00e9rentielle.\n  <\/li>\n<\/ul>\n<\/li>\n<li>\n<ul>\n<\/ul>\n<\/li>\n<li>\n<ul>\n<li>\n    Que vaut le nombre de Reynolds aux premiers instants du mouvement ?\n  <\/li>\n<\/ul>\n<\/li>\n<li>\n<ul>\n<li>\n    On peut utiliser la compr\u00e9hension de liste : <code>L[:,:]<\/code> par exemple pour prendre toutes les lignes et toutes les colonnes d\u2019un tableau <code>L<\/code>.\n  <\/li>\n<li>\n    Rappeler l\u2019expression du nombre de Reynolds en fonction de la vitesse.\n  <\/li>\n<li>\n    Rappeler l\u2019expression de la force de train\u00e9e en fonction du coefficient de train\u00e9e.\n  <\/li>\n<\/ul>\n<\/li>\n<li>\n<ul>\n<li>\n    Seule la fonction <code>dvdt<\/code> doit \u00eatre modifi\u00e9e pour prendre en compte la nouvelle expression de la force de train\u00e9e.\n  <\/li>\n<\/ul>\n<\/li>\n<\/ol>\n<h5>Exercice 9<\/h5>\n<ol>\n<li>\n<ul>\n<li>\n    Faire un sch\u00e9ma en faisant appara\u00eetre les forces en pr\u00e9sence sur le voilier.\n  <\/li>\n<\/ul>\n<\/li>\n<\/ol>\n<h5>Exercice 10<\/h5>\n<ol>\n<li>\n<ul>\n<li>\n    Appliquer le th\u00e9or\u00e8me de la r\u00e9sultante cin\u00e9tique au ballon.\n  <\/li>\n<\/ul>\n<\/li>\n<li>\n<ul>\n<\/ul>\n<\/li>\n<li>\n<ul>\n<\/ul>\n<\/li>\n<li>\n<ul>\n<li>\n    La trajectoire du ballon passe-t-elle par les cages ?\n  <\/li>\n<\/ul>\n<\/li>\n<li>\n<ul>\n<li>\n    Comment s\u2019exprime la force de train\u00e9e ?\n  <\/li>\n<\/ul>\n<\/li>\n<li>\n<ul>\n<\/ul>\n<\/li>\n<\/ol><\/div>\n","protected":false},"excerpt":{"rendered":"<p>T\u00e9l\u00e9chargements Polycopi\u00e9 Flashcards Anki Coups de pouce Laisser la souris\/taper sur le texte pour l&rsquo;afficher. Exercice 1 Relier la masse volumique \u00e0 la pression gr\u00e2ce \u00e0 l\u2019\u00e9quation d\u2019\u00e9tat des gaz parfaits. R\u00e9soudre l\u2019\u00e9quation fondamentale de l\u2019hydrostatique. On consid\u00e8re un cylindre&hellip;<\/p>\n<p class=\"more-link-p\"><a class=\"more-link\" href=\"https:\/\/www.cpge-brizeux.fr\/wordpress\/psi\/physchim-psi-2526\/phenomenes-de-transport-4-fluide-en-ecoulement-2.html\">Read more &rarr;<\/a><\/p>\n","protected":false},"author":26,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[430],"tags":[],"class_list":["post-37681","post","type-post","status-publish","format-standard","hentry","category-physchim-psi-2526"],"_links":{"self":[{"href":"https:\/\/www.cpge-brizeux.fr\/wordpress\/wp-json\/wp\/v2\/posts\/37681","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.cpge-brizeux.fr\/wordpress\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.cpge-brizeux.fr\/wordpress\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.cpge-brizeux.fr\/wordpress\/wp-json\/wp\/v2\/users\/26"}],"replies":[{"embeddable":true,"href":"https:\/\/www.cpge-brizeux.fr\/wordpress\/wp-json\/wp\/v2\/comments?post=37681"}],"version-history":[{"count":0,"href":"https:\/\/www.cpge-brizeux.fr\/wordpress\/wp-json\/wp\/v2\/posts\/37681\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.cpge-brizeux.fr\/wordpress\/wp-json\/wp\/v2\/media?parent=37681"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.cpge-brizeux.fr\/wordpress\/wp-json\/wp\/v2\/categories?post=37681"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.cpge-brizeux.fr\/wordpress\/wp-json\/wp\/v2\/tags?post=37681"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}