{"id":37770,"date":"2026-01-12T01:59:11","date_gmt":"2026-01-11T23:59:11","guid":{"rendered":"https:\/\/www.cpge-brizeux.fr\/wordpress\/non-classe\/bilans-macroscopiques-2.html"},"modified":"2026-01-22T11:45:57","modified_gmt":"2026-01-22T09:45:57","slug":"bilans-macroscopiques-2","status":"publish","type":"post","link":"https:\/\/www.cpge-brizeux.fr\/wordpress\/psi\/physchim-psi-2526\/bilans-macroscopiques-2.html","title":{"rendered":"Bilans macroscopiques"},"content":{"rendered":"<h2>T\u00e9l\u00e9chargements<\/h2>\n<p><a href='https:\/\/www.cpge-brizeux.fr\/wordpress\/wp-content\/uploads\/bilans-macroscopiques-poly.pdf'>Polycopi\u00e9<\/a><\/p>\n<p><a href='https:\/\/www.cpge-brizeux.fr\/wordpress\/wp-content\/uploads\/bilans-macroscopiques-flashcards.apkg'>Flashcards Anki<\/a><\/p>\n<h2>Coups de pouce<\/h2>\n<p>Laisser la souris\/taper sur le texte pour l&rsquo;afficher.<\/p>\n<div class='coups-de-pouce'>\n<h5>Exercice 1<\/h5>\n<ol>\n<li>\n<ul>\n<li>\n    Il s\u2019agit de la d\u00e9monstration du PPI du cours, avec quelques hypoth\u00e8ses qui simplifient un peu les calculs.\n  <\/li>\n<li>\n    Le PPI ainsi obtenu doit \u00eatre multipli\u00e9 par le d\u00e9bit massique pour faire apparaitre les puissance demand\u00e9es.\n  <\/li>\n<\/ul>\n<\/li>\n<li>\n<ul>\n<li>\n    Donner un nom \u00e0 la puissance allant du gaz vers le fluide.\n  <\/li>\n<li>\n    Appliquer le PPI en termes de puissances d\u2019une part au gaz et d\u2019autre part au fluides.\n  <\/li>\n<li>\n    Utiliser la seconde loi de Joule.\n  <\/li>\n<\/ul>\n<\/li>\n<li>\n<ul>\n<li>\n    \u00c9crire le second principe de la thermodynamique pour un syst\u00e8me ouvert en \u00e9coulement stationnaire. Comment le transformer pour faire apparaitre le taux de cr\u00e9ation d\u2019entropie ?\n  <\/li>\n<li>\n    Il faut utiliser la m\u00eame m\u00e9thode que pour faire apparaitre des puissances dans le PPI.\n  <\/li>\n<li>\n    Appliquer cette relation tant\u00f4t au gaz, tant\u00f4t \u00e0 l\u2019eau, puis faire la somme des deux.\n  <\/li>\n<li>\n    L\u2019entropie \u00e9chang\u00e9e re\u00e7ue par le gaz est celle c\u00e9d\u00e9e par l\u2019eau.\n  <\/li>\n<\/ul>\n<\/li>\n<li>\n<ul>\n<li>\n    Comment s\u2019\u00e9crit la variation d\u2019enthalpie pour une transformation isobare ?\n  <\/li>\n<li>\n    \u00c9crire la seconde loi de Joule.\n  <\/li>\n<li>\n    Exprimer la variation d\u2019entropie massique en fonction de la capacit\u00e9 thermique massique et de la temp\u00e9rature.\n  <\/li>\n<li>\n    Pour un gaz parfait, comment la capacit\u00e9 thermique massique \u00e0 pression constant s\u2019exprime-t-elle en fonction du coefficient de Laplace ?\n  <\/li>\n<\/ul>\n<\/li>\n<li>\n<ul>\n<\/ul>\n<\/li>\n<\/ol>\n<h5>Exercice 2<\/h5>\n<ol>\n<li>\n<ul>\n<\/ul>\n<\/li>\n<\/ol>\n<h5>Exercice 3<\/h5>\n<ol>\n<li>\n<ul>\n<li>\n    Attention, pour les eaux grises, l\u2019eau rentre en <span style=\"display: inline-block\"><svg class=\"typst-frame\" style=\"overflow: visible; width: 2.860222222222222em; height: 0.683em;\" viewBox=\"0 0 31.462444444444444 7.513000000000001\" width=\"31.462444444444444pt\" height=\"7.513000000000001pt\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" xmlns:xlink=\"http:\/\/www.w3.org\/1999\/xlink\" xmlns:h5=\"http:\/\/www.w3.org\/1999\/xhtml\"><g><g class=\"typst-text\" transform=\"matrix(1 0 0 -1 0 7.513000000000001)\"><use xlink:href=\"#gDA15FC2A8EB4A366D1ACDAC682DCF075\" x=\"0\" y=\"0\" fill=\"#000000\" fill-rule=\"nonzero\"\/><\/g><g class=\"typst-text\" transform=\"matrix(1 0 0 -1 8.736444444444444 7.513000000000001)\"><use xlink:href=\"#gCACA831666848D2A0C05D471064B6086\" x=\"0\" y=\"0\" fill=\"#000000\" 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en s\u00e9rie ou en parall\u00e8le ?\n  <\/li>\n<\/ul>\n<\/li>\n<li>\n<ul>\n<\/ul>\n<\/li>\n<li>\n<ul>\n<li>\n    La conductivit\u00e9 du b\u00e9ton a \u00e9t\u00e9 vue en cours.\n  <\/li>\n<\/ul>\n<\/li>\n<li>\n<ul>\n<\/ul>\n<\/li>\n<li>\n<ul>\n<\/ul>\n<\/li>\n<li>\n<ul>\n<li>\n    On peut appliquer le PPI sur la conduite d\u2019eau potable en entier.\n  <\/li>\n<\/ul>\n<\/li>\n<\/ol>\n<h5>Exercice 4<\/h5>\n<ol>\n<li>\n<ul>\n<\/ul>\n<\/li>\n<li>\n<ul>\n<li>\n    Quelles sont les trois forces s\u2019appliquant sur le syst\u00e8me ?\n  <\/li>\n<li>\n    Les 3 forces sont les deux forces de pression et la force <span style=\"display: inline-block\"><svg class=\"typst-frame\" style=\"overflow: visible; width: 2.769em; height: 0.683em;\" viewBox=\"0 0 30.459 7.513000000000001\" width=\"30.459pt\" height=\"7.513000000000001pt\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" xmlns:xlink=\"http:\/\/www.w3.org\/1999\/xlink\" xmlns:h5=\"http:\/\/www.w3.org\/1999\/xhtml\"><g><g class=\"typst-text\" 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En d\u00e9duire une relation entre <span style=\"display: inline-block\"><svg class=\"typst-frame\" style=\"overflow: visible; width: 0.49600000000000005em; height: 0.683em;\" viewBox=\"0 0 5.456 7.513000000000001\" width=\"5.456pt\" height=\"7.513000000000001pt\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" xmlns:xlink=\"http:\/\/www.w3.org\/1999\/xlink\" xmlns:h5=\"http:\/\/www.w3.org\/1999\/xhtml\"><g><g class=\"typst-text\" transform=\"matrix(1 0 0 -1 0 7.513000000000001)\"><use xlink:href=\"#g4AAFF496A0260C0F84F20508E52FAA05\" x=\"0\" y=\"0\" fill=\"#000000\" fill-rule=\"nonzero\"\/><\/g><\/g><defs id=\"glyph\"><symbol id=\"g4AAFF496A0260C0F84F20508E52FAA05\" overflow=\"visible\"><path d=\"M 0 0m 4.059 4.301 c 0 -0.0880003 0.09899998 -0.23099995 0.2750001 -0.4510002 c 0.17599964 -0.22000003 0.26399994 -0.4729998 0.26399994 -0.7589998 c 0 -0.319 -0.15400028 -0.85800004 -0.47300005 -1.6170001 c -0.23099995 -0.528 -0.75900006 -1.276 -1.408 -1.276 c -0.50600004 0 -0.75900006 0.297 -0.75900006 0.902 c 0 0.42900002 0.20900011 1.1880001 0.6270001 2.277 c 0.08800006 0.23099995 0.13199997 0.41799998 0.13199997 0.54999995 c 0 0.5499997 -0.37400007 0.93499994 -0.924 0.93499994 c -0.48399997 0 -0.86899996 -0.2750001 -1.144 -0.8249998 c -0.22 -0.4510002 -0.32999998 -0.7370002 -0.32999998 -0.8800001 c 0 -0.09899998 0.055000007 -0.15400004 0.176 -0.15400004 c 0.143 0 0.16499996 0.065999985 0.20899999 0.22000003 c 0.25300002 0.8800001 0.605 1.3199997 1.056 1.3199997 c 0.143 0 0.22000003 -0.09899998 0.22000003 -0.3079996 c 0 -0.17600012 -0.055000067 -0.41800022 -0.176 -0.7370002 c -0.40700006 -1.089 -0.61600006 -1.826 -0.61600006 -2.2329998 c 0 -0.561 0.18700004 -0.946 0.561 -1.155 c 0.29700005 -0.154 0.60500014 -0.231 0.92400014 -0.231 c 0.97899985 0 1.661 1.056 1.9469998 1.903 c 0.35200024 1.034 0.5279999 1.7930001 0.5279999 2.277 c 0 0.53900003 -0.17599964 0.803 -0.5169997 0.803 c -0.2750001 0 -0.572 -0.28599977 -0.572 -0.5609999 Z \"\/><\/symbol><\/defs><\/svg><\/span> et <span style=\"display: inline-block\"><svg class=\"typst-frame\" style=\"overflow: visible; width: 0.8369em; height: 0.683em;\" viewBox=\"0 0 9.2059 7.513000000000001\" width=\"9.2059pt\" height=\"7.513000000000001pt\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" xmlns:xlink=\"http:\/\/www.w3.org\/1999\/xlink\" xmlns:h5=\"http:\/\/www.w3.org\/1999\/xhtml\"><g><g class=\"typst-text\" transform=\"matrix(1 0 0 -1 0 7.513000000000001)\"><use xlink:href=\"#g4AAFF496A0260C0F84F20508E52FAA05\" x=\"0\" y=\"0\" fill=\"#000000\" fill-rule=\"nonzero\"\/><\/g><g class=\"typst-text\" transform=\"matrix(1 0 0 -1 5.456 3.5200000000000005)\"><use xlink:href=\"#g5D5B2F46E10CC3D74D46D6CB245D43A2\" x=\"0\" y=\"0\" fill=\"#000000\" fill-rule=\"nonzero\"\/><\/g><\/g><defs id=\"glyph\"><symbol id=\"g4AAFF496A0260C0F84F20508E52FAA05\" overflow=\"visible\"><path d=\"M 0 0m 4.059 4.301 c 0 -0.0880003 0.09899998 -0.23099995 0.2750001 -0.4510002 c 0.17599964 -0.22000003 0.26399994 -0.4729998 0.26399994 -0.7589998 c 0 -0.319 -0.15400028 -0.85800004 -0.47300005 -1.6170001 c -0.23099995 -0.528 -0.75900006 -1.276 -1.408 -1.276 c -0.50600004 0 -0.75900006 0.297 -0.75900006 0.902 c 0 0.42900002 0.20900011 1.1880001 0.6270001 2.277 c 0.08800006 0.23099995 0.13199997 0.41799998 0.13199997 0.54999995 c 0 0.5499997 -0.37400007 0.93499994 -0.924 0.93499994 c -0.48399997 0 -0.86899996 -0.2750001 -1.144 -0.8249998 c -0.22 -0.4510002 -0.32999998 -0.7370002 -0.32999998 -0.8800001 c 0 -0.09899998 0.055000007 -0.15400004 0.176 -0.15400004 c 0.143 0 0.16499996 0.065999985 0.20899999 0.22000003 c 0.25300002 0.8800001 0.605 1.3199997 1.056 1.3199997 c 0.143 0 0.22000003 -0.09899998 0.22000003 -0.3079996 c 0 -0.17600012 -0.055000067 -0.41800022 -0.176 -0.7370002 c -0.40700006 -1.089 -0.61600006 -1.826 -0.61600006 -2.2329998 c 0 -0.561 0.18700004 -0.946 0.561 -1.155 c 0.29700005 -0.154 0.60500014 -0.231 0.92400014 -0.231 c 0.97899985 0 1.661 1.056 1.9469998 1.903 c 0.35200024 1.034 0.5279999 1.7930001 0.5279999 2.277 c 0 0.53900003 -0.17599964 0.803 -0.5169997 0.803 c -0.2750001 0 -0.572 -0.28599977 -0.572 -0.5609999 Z \"\/><\/symbol><symbol id=\"g5D5B2F46E10CC3D74D46D6CB245D43A2\" overflow=\"visible\"><path d=\"M 0 0m 2.1868 4.2273 c -0.1925 0 -0.32340002 -0.07700014 -0.39269996 -0.23870015 l -1.2936001 -3.2494001 h 0.34649998 l 1.7094 2.8259 c 0.038499832 0.06929994 0.06159997 0.14630008 0.06159997 0.23099995 c 0 0.23100019 -0.20020008 0.43120027 -0.43120003 0.43120027 Z \"\/><\/symbol><\/defs><\/svg><\/span>.\n  <\/li>\n<\/ul>\n<\/li>\n<li>\n<ul>\n<li>\n    Justifier que la r\u00e9sultante des forces de pression est nulle.\n  <\/li>\n<\/ul>\n<\/li>\n<li>\n<ul>\n<\/ul>\n<\/li>\n<li>\n<ul>\n<li>\n    D\u00e9finir un syst\u00e8me ferm\u00e9 \u00e0 partir du syst\u00e8me ouvert d\u00e9limit\u00e9 par <span style=\"display: inline-block\"><svg class=\"typst-frame\" style=\"overflow: visible; width: 1.0673em; height: 0.683em;\" viewBox=\"0 0 11.7403 7.513000000000001\" width=\"11.7403pt\" 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id=\"g35089A96F4517D19458AAA3BAF36FB65\" overflow=\"visible\"><path d=\"M 0 0m 0.9163 3.2648 c 0.24639994 0 0.43119997 0.18479991 0.43119997 0.43120003 c 0 0.27719998 -0.14629996 0.42350006 -0.43119997 0.43120003 c 0.16940004 0.36189985 0.5544 0.6545 1.0548999 0.6545 c 0.6775999 0 1.1242001 -0.50820017 1.1242001 -1.1858001 c 0 -0.36960006 -0.13090014 -0.7238002 -0.40040016 -1.0703001 c -0.1308999 -0.17709994 -0.23099995 -0.30029988 -0.30029988 -0.36960006 l -1.8249 -1.8094999 c -0.10010001 -0.092400014 -0.08470002 -0.1155 -0.08470002 -0.3465 h 3.1724 l 0.23869991 1.4476 h -0.32340002 c -0.053900003 -0.4081 -0.11549997 -0.64680004 -0.18479991 -0.7007 c -0.03850007 -0.023100019 -0.27719998 -0.03850001 -0.7314999 -0.03850001 h -1.3090001 c 0.5159 0.45429993 0.9933001 0.86239994 1.4476 1.2243 c 0.34649992 0.2694999 0.59290004 0.50820005 0.7469001 0.71609986 c 0.23099995 0.30030012 0.34649992 0.6160002 0.34649992 0.94710016 c 0 0.47739983 -0.18479991 0.8547001 -0.56209993 1.1318998 c 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\"\/><\/symbol><symbol id=\"gF5D9BA8817F2BD930E2EAB9A521B4E93\" overflow=\"visible\"><path d=\"M 0 0m 7.3259997 -0.495 c 0.18700027 -0.07700002 0.38500023 0.066000015 0.38500023 0.24200001 c 0 0.109999985 -0.05499983 0.18699999 -0.1539998 0.23099999 l -5.874 2.772 l 5.874 2.7719998 c 0.09899998 0.04400015 0.1539998 0.12100029 0.1539998 0.22000027 c 0 0.1869998 -0.08799982 0.2750001 -0.26399994 0.2750001 c -0.04400015 0 -0.0880003 -0.011000156 -0.12100029 -0.022000313 l -6.3139997 -2.9919999 c -0.109999955 -0.055000067 -0.16499996 -0.13199997 -0.16499996 -0.25300002 c 0 -0.12100005 0.055000007 -0.19799995 0.16499996 -0.25300002 Z \"\/><\/symbol><symbol id=\"g5B5423168B00904C32F30889AB61FA69\" overflow=\"visible\"><path d=\"M 0 0m 2.3331 5.1128 c -0.3311 -0.32340002 -0.8239001 -0.48510027 -1.4938002 -0.48510027 v -0.33879995 c 0.4543 0 0.81619996 0.069300175 1.0934 0.20020008 v -3.8346 c 0 -0.10010004 -0.0077000856 -0.16170001 -0.030800104 -0.1925 c -0.03849995 -0.08470002 -0.2694999 -0.13090003 -0.69299996 -0.13090003 h -0.3157 v -0.3311 l 1.3706 0.0308 l 1.3783002 -0.0308 v 0.3311 h -0.31570005 c -0.42350006 0 -0.6545 0.046200007 -0.70070004 0.13090003 c -0.015399933 0.030799985 -0.0230999 0.092399955 -0.0230999 0.1925 v 4.2118998 c 0 0.20790005 -0.030800104 0.24640036 -0.26950002 0.24640036 Z \"\/><\/symbol><\/defs><\/svg><\/span>.\n  <\/li>\n<\/ul>\n<\/li>\n<\/ol>\n<h5>Exercice 5<\/h5>\n<ol>\n<li>\n<ul>\n<li>\n    En supposant l\u2019\u00e9coulement parfait, stationnaire, incompressible et homog\u00e8ne, \u00e9tablir l\u2019expression de la vitesse au niveau de la vanne.\n  <\/li>\n<li>\n    Relier le d\u00e9bit volumique \u00e0 la vitesse de l\u2019\u00e9coulement au niveau de la vanne.\n  <\/li>\n<li>\n    Relier le volume d\u2019eau dans la cuve \u00e0 la hauteur d\u2019eau.\n  <\/li>\n<li>\n    Formuler une \u00e9quation diff\u00e9rentielle sur la hauteur ou le volume d\u2019eau puis l\u2019int\u00e9grer.\n  <\/li>\n<li>\n    L\u2019\u00e9quation 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-0.4311998 0.15400001 -0.4311998 0.462 c 0 0.11549997 0.1308999 0.69299996 0.39269996 1.7170999 c 0.1308999 0.50049996 0.36189985 0.75460005 0.7084 0.75460005 l 0.06929994 -0.0076999664 c 0.092400074 0 0.18479991 -0.0230999 0.26950002 -0.06159997 c -0.19250011 -0.08470011 -0.28489995 -0.22329998 -0.28489995 -0.42350006 c 0 -0.18479991 0.14629984 -0.31570005 0.3311 -0.31570005 c 0.2617998 0 0.45429993 0.23100019 0.45429993 0.4928 Z \"\/><\/symbol><\/defs><\/svg><\/span>\n  <\/li>\n<li>\n    Estimer la section de la vanne \u00e0 partir de la photo.\n  <\/li>\n<\/ul>\n<\/li>\n<\/ol>\n<h5>Exercice 6<\/h5>\n<ol>\n<li>\n<ul>\n<li>\n    \u00c9crire la relation de Bernoulli entre la section gauche et l\u2019\u00e9largissement.\n  <\/li>\n<\/ul>\n<\/li>\n<li>\n<ul>\n<li>\n    Repr\u00e9senter sur un sch\u00e9ma les forces de pression s\u2019exer\u00e7ant tout autour du syst\u00e8me. 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Exercice 1 Il s\u2019agit de la d\u00e9monstration du PPI du cours, avec quelques hypoth\u00e8ses qui simplifient un peu les calculs. Le PPI ainsi obtenu doit&hellip;<\/p>\n<p class=\"more-link-p\"><a class=\"more-link\" href=\"https:\/\/www.cpge-brizeux.fr\/wordpress\/psi\/physchim-psi-2526\/bilans-macroscopiques-2.html\">Read more &rarr;<\/a><\/p>\n","protected":false},"author":26,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[430],"tags":[],"class_list":["post-37770","post","type-post","status-publish","format-standard","hentry","category-physchim-psi-2526"],"_links":{"self":[{"href":"https:\/\/www.cpge-brizeux.fr\/wordpress\/wp-json\/wp\/v2\/posts\/37770","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.cpge-brizeux.fr\/wordpress\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.cpge-brizeux.fr\/wordpress\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.cpge-brizeux.fr\/wordpress\/wp-json\/wp\/v2\/users\/26"}],"replies":[{"embeddable":true,"href":"https:\/\/www.cpge-brizeux.fr\/wordpress\/wp-json\/wp\/v2\/comments?post=37770"}],"version-history":[{"count":1,"href":"https:\/\/www.cpge-brizeux.fr\/wordpress\/wp-json\/wp\/v2\/posts\/37770\/revisions"}],"predecessor-version":[{"id":37929,"href":"https:\/\/www.cpge-brizeux.fr\/wordpress\/wp-json\/wp\/v2\/posts\/37770\/revisions\/37929"}],"wp:attachment":[{"href":"https:\/\/www.cpge-brizeux.fr\/wordpress\/wp-json\/wp\/v2\/media?parent=37770"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.cpge-brizeux.fr\/wordpress\/wp-json\/wp\/v2\/categories?post=37770"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.cpge-brizeux.fr\/wordpress\/wp-json\/wp\/v2\/tags?post=37770"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}